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Yahoo!
 3 years ago
P.E of a particle free to move to along xaxis is given by (x^3  x^2/2)J where x is in metre . The particle is initially kept at x=0 and then given a sight displacement x in +ve direction. The force acting on the particle will displace it to a Distance ?
Yahoo!
 3 years ago
P.E of a particle free to move to along xaxis is given by (x^3  x^2/2)J where x is in metre . The particle is initially kept at x=0 and then given a sight displacement x in +ve direction. The force acting on the particle will displace it to a Distance ?

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Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.0@experimentX @JFraser @siddhantsharan @gerryliyana

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2F = 0 ... find the equilibrium
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