anonymous
  • anonymous
P.E of a particle free to move to along x-axis is given by (x^3 - x^2/2)J where x is in metre . The particle is initially kept at x=0 and then given a sight displacement x in +ve direction. The force acting on the particle will displace it to a Distance ?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@experimentX @JFraser @siddhantsharan @gerryliyana
anonymous
  • anonymous
@ghazi
experimentX
  • experimentX
F = - d(PE)/dx

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anonymous
  • anonymous
- (3x^2 - x)
experimentX
  • experimentX
F = 0 ... find the equilibrium
anonymous
  • anonymous
x = 1/3
anonymous
  • anonymous
Thxx.)

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