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baldymcgee6
Group Title
Difference between negative exponent and inverse functions?
For example,
sine inverse: sin^1(x)
or
1/(sin(x)) = (sin(x))^1
 2 years ago
 2 years ago
baldymcgee6 Group Title
Difference between negative exponent and inverse functions? For example, sine inverse: sin^1(x) or 1/(sin(x)) = (sin(x))^1
 2 years ago
 2 years ago

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campbell_st Group TitleBest ResponseYou've already chosen the best response.1
the negative indice means to find the reciprocal of sin(x) so given \[\sin(x) = \frac{\sin(x)}{1}\] then the reciprocal is \[(\frac{\sin(x)}{1})^{1} = \frac{1}{\sin(x)}\] and for the inverse function if \[\sin(x) = \frac{a}{b}\] the sin of an angle is equal to a ratio then \[x = \sin^{1}(\frac{a}{b})\] the angle is equal to the inverse sin of the ratio. its the 2 way connection between and angle and a ratio. hope it helps.
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353436712645:dw
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
thats correct.....
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353436831708:dw
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
@campbell_st
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353437026561:dw
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
ok.... this is where indices and trig seem to clash \[(\sin(x))^2 = \sin^2(x)\] and \[(\frac{(\sin(x))}{1})^{2} = \frac{1}{(\sin(x))^2} = \frac{1}{\sin^2(x)}\]
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
hope that makes some sense... the inverse trig is only ever written as \[\sin^{1}(a)\]
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
Okay, thanks so much for the clarification.
 2 years ago
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