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lima345 Group Title

Using the following equation: F = ma Solve for m.

  • one year ago
  • one year ago

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  1. jlongSwag27 Group Title
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    To solve for m, divide both sides by a, F/a=ma/a, so m = F/a.

    • one year ago
  2. stewie Group Title
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    force = mass x acceleration

    • one year ago
  3. stewie Group Title
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    hes right

    • one year ago
  4. Yahoo! Group Title
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    Divide by 'a' on both sides F/a = m

    • one year ago
  5. lima345 Group Title
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    Solve for H: V=LWH

    • one year ago
  6. skullpatrol Group Title
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    As long as a is not equal to 0.

    • one year ago
  7. jlongSwag27 Group Title
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    v = l*w*h v / (l*w) = (l*w*h) / (l*w) v /(l*w) = h h = v / (l*w) When you divide the circumference of a circle by its diameter you always get the same number. This number is called pi and it is 22 / 7 or 3.14. A = pi*r^2 is the formula that is used to find the area of a circle given its dimeter/radius.

    • one year ago
  8. lima345 Group Title
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    During an experiment that Paul and Dawn performed, the stretch of a spring was directly proportional to the force applied to the spring. When they put the data on a graph they would expect to have what type of curve?

    • one year ago
  9. jlongSwag27 Group Title
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    Make a new thread @lima345

    • one year ago
  10. jlongSwag27 Group Title
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    Well, Force= (spring constant) X (displacement) The k value is a constant, so F=x So if I'm not mistaken, the graph should be a diagonal straight line because the force always equals the displacement of the spring. Make sense?

    • one year ago
  11. lima345 Group Title
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    Find the slope of the line containing the two points (1,-1) and (-5,-3).

    • one year ago
  12. jlongSwag27 Group Title
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    -7/2

    • one year ago
  13. lima345 Group Title
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    If X = 5 and Y =3, what does Z equal? 2X + 2Z = 10Y

    • one year ago
  14. jlongSwag27 Group Title
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    your not going to learn anything if i just give you the answers & post it in a new thread

    • one year ago
  15. lima345 Group Title
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    JUST HELP ME WITH THAT ONE

    • one year ago
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