anonymous
  • anonymous
Helpp
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@jim_thompson5910 @Nameless
jim_thompson5910
  • jim_thompson5910
sin(3x) = sin(2x + x) sin(3x) = sin(2x)cos(x) + cos(2x)sin(x) sin(3x) = sin(x+x)cos(x) + cos(x+x)sin(x) sin(3x) = [sin(x)cos(x) + cos(x)sin(x)]cos(x) + [cos(x)cos(x) - sin(x)sin(x)]sin(x) sin(3x) = [2cos(x)sin(x)]cos(x) + [cos^2(x) - sin^2(x)]sin(x) sin(3x) = 2cos^2(x)sin(x) + cos^2(x)sin(x) - sin^3(x) Do the same to find cos(3x)
jim_thompson5910
  • jim_thompson5910
I'm using the identities sin(x+y) = sin(x)cos(y) + cos(x)sin(y) cos(x+y) = cos(x)cos(y) - sin(x)sin(y)

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jim_thompson5910
  • jim_thompson5910
sry i should have gone further sin(3x) = 3cos^2(x)sin(x) - sin^3(x)
anonymous
  • anonymous
im confused can you tell me what the answer is so i can check if i got it right?
jim_thompson5910
  • jim_thompson5910
hold on one sec
jim_thompson5910
  • jim_thompson5910
checking the answer, but the second one doesn't seem right, but one sec
anonymous
  • anonymous
ok thank you
jim_thompson5910
  • jim_thompson5910
well using a graphing calculator, I was able to eliminate choices A through C so that leaves D

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