## anonymous 3 years ago 4 = the square root of p, -2?

• This Question is Open
1. zepdrix

$\huge 4=\sqrt p$To solve for p, square both sides.$\huge 4^2=\sqrt{p}^2$$\huge p=4^2$Is this what you were trying to do? Solve for p? :D

2. zepdrix

os was there a minus 2 in the problem also? :O i couldn't tell based on the comma, i thought maybe that was a guess :D

3. anonymous

Yes there is a minus 2 . So does it just become p = 2^2 ?

4. zepdrix

$\huge 4=\sqrt p - 2$So this is the problem? :D

5. zepdrix

We'll add 2 to both sides, giving us:$\huge 6=\sqrt p$Then we'll do the same step we did before, square both sides, that will eliminate the square root.$\huge 6^2=\sqrt p ^2 \qquad \rightarrow \qquad 6^2=p$

6. anonymous

Thanks so much !!

7. anonymous

I understand how to do the rest of the problems now (: