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sabika13
solve for x in the given interval sinxtan3x=0(-pi,0)
given sinx tan3x=0 means either sinx=0 or tan3x=0 if sinx=0 then x=n(pi) where n is an integer if tan3x=0 then 3x=m(pi) where m is an integer for getting the values in the given inter use proper values for n and m and thus the answer are 0.-(pi)/3,-2(pi)/3,-pi etc..
how is -2pi/3 in the interval?
when m=2 in 3x=mpi and it is less than -pi also tan3(-2(pi)/3))=0