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bev199
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I need help on this problem I don't understand how to factor this a^26a+8
 2 years ago
 2 years ago
bev199 Group Title
I need help on this problem I don't understand how to factor this a^26a+8
 2 years ago
 2 years ago

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CarolineJean Group TitleBest ResponseYou've already chosen the best response.0
is it factoring?
 2 years ago

CarolineJean Group TitleBest ResponseYou've already chosen the best response.0
(a4) (a2)
 2 years ago

bev199 Group TitleBest ResponseYou've already chosen the best response.0
yes its factoring I see the a^2 and the 8 but where is the 6a?
 2 years ago

bev199 Group TitleBest ResponseYou've already chosen the best response.0
Carolinejean are you still there?
 2 years ago

freakeo98 Group TitleBest ResponseYou've already chosen the best response.0
dude thats the answer.
 2 years ago

mastr_nush Group TitleBest ResponseYou've already chosen the best response.0
think of if this way ... the format of a quadratic is \[ax^2+bx+c=0\] right ? to factor, think of what 2 numbers multiply to make up c or in this case +8, and at the same time add to b or in this case 6 ... \[2*4=8\] and \[2 + 4 =6\]... so we write \[(x2)(x3)=0\] and to solve, since it is a multiplication of 2 terms, then we should have 2 cases where this is valid :\[(x2)=0 ==> x=2\] or \[(x3)=0 ==> x=3\] voila!
 2 years ago
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