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bev199
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I need help on this problem I don't understand how to factor this a^26a+8
 one year ago
 one year ago
bev199 Group Title
I need help on this problem I don't understand how to factor this a^26a+8
 one year ago
 one year ago

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CarolineJean Group TitleBest ResponseYou've already chosen the best response.0
is it factoring?
 one year ago

CarolineJean Group TitleBest ResponseYou've already chosen the best response.0
(a4) (a2)
 one year ago

bev199 Group TitleBest ResponseYou've already chosen the best response.0
yes its factoring I see the a^2 and the 8 but where is the 6a?
 one year ago

bev199 Group TitleBest ResponseYou've already chosen the best response.0
Carolinejean are you still there?
 one year ago

freakeo98 Group TitleBest ResponseYou've already chosen the best response.0
dude thats the answer.
 one year ago

mastr_nush Group TitleBest ResponseYou've already chosen the best response.0
think of if this way ... the format of a quadratic is \[ax^2+bx+c=0\] right ? to factor, think of what 2 numbers multiply to make up c or in this case +8, and at the same time add to b or in this case 6 ... \[2*4=8\] and \[2 + 4 =6\]... so we write \[(x2)(x3)=0\] and to solve, since it is a multiplication of 2 terms, then we should have 2 cases where this is valid :\[(x2)=0 ==> x=2\] or \[(x3)=0 ==> x=3\] voila!
 one year ago
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