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bev199
 2 years ago
Best ResponseYou've already chosen the best response.0yes its factoring I see the a^2 and the 8 but where is the 6a?

bev199
 2 years ago
Best ResponseYou've already chosen the best response.0Carolinejean are you still there?

freakeo98
 2 years ago
Best ResponseYou've already chosen the best response.0dude thats the answer.

mastr_nush
 2 years ago
Best ResponseYou've already chosen the best response.0think of if this way ... the format of a quadratic is \[ax^2+bx+c=0\] right ? to factor, think of what 2 numbers multiply to make up c or in this case +8, and at the same time add to b or in this case 6 ... \[2*4=8\] and \[2 + 4 =6\]... so we write \[(x2)(x3)=0\] and to solve, since it is a multiplication of 2 terms, then we should have 2 cases where this is valid :\[(x2)=0 ==> x=2\] or \[(x3)=0 ==> x=3\] voila!
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