A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

bev199
 2 years ago
Best ResponseYou've already chosen the best response.0yes its factoring I see the a^2 and the 8 but where is the 6a?

bev199
 2 years ago
Best ResponseYou've already chosen the best response.0Carolinejean are you still there?

freakeo98
 2 years ago
Best ResponseYou've already chosen the best response.0dude thats the answer.

mastr_nush
 2 years ago
Best ResponseYou've already chosen the best response.0think of if this way ... the format of a quadratic is \[ax^2+bx+c=0\] right ? to factor, think of what 2 numbers multiply to make up c or in this case +8, and at the same time add to b or in this case 6 ... \[2*4=8\] and \[2 + 4 =6\]... so we write \[(x2)(x3)=0\] and to solve, since it is a multiplication of 2 terms, then we should have 2 cases where this is valid :\[(x2)=0 ==> x=2\] or \[(x3)=0 ==> x=3\] voila!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.