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iheartfood Group TitleBest ResponseYou've already chosen the best response.0
dw:1353461289646:dw
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
this is the question, in case my handwriting/drawing is hard to see :P
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
answer choices A,B,C,D from top to bottom :)
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
how'd u get that? :O
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
im not quite sure if i am understanding this right, but did u just make the 5x not an exponent, so that takes out the ln, so you get e=5x ?? idk is that right?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
ln is a natural log which 'undoes' the exponential function with 'e' as a base so basically ln(e^x) = x and e^[ ln(x) ] = x which tells you that f(x) = ln(x) and g(x) = e^x are inverse functions
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
okay, wait so my answer is ln(x) ? or is it ln(5x) ?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
no i'm just saying in general
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
wait scratch that... there is no ln(5x) haha my bad... or is it just 5x ?
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
ohhh okay :P i see
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
in my example, replace each 'x' with '5x'
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
okay :) so my answer is B. 5x because of that? since e=x ? and x = 5x ?
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
is that right? since u said e=x right?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you are correct, and no i didn't say e = x
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
not sure where you got that
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
i gotcha
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.0
oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)
 one year ago
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