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anonymous
 4 years ago
question inside :)
anonymous
 4 years ago
question inside :)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353461289646:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is the question, in case my handwriting/drawing is hard to see :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0answer choices A,B,C,D from top to bottom :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im not quite sure if i am understanding this right, but did u just make the 5x not an exponent, so that takes out the ln, so you get e=5x ?? idk is that right?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1ln is a natural log which 'undoes' the exponential function with 'e' as a base so basically ln(e^x) = x and e^[ ln(x) ] = x which tells you that f(x) = ln(x) and g(x) = e^x are inverse functions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, wait so my answer is ln(x) ? or is it ln(5x) ?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1no i'm just saying in general

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait scratch that... there is no ln(5x) haha my bad... or is it just 5x ?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1in my example, replace each 'x' with '5x'

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay :) so my answer is B. 5x because of that? since e=x ? and x = 5x ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that right? since u said e=x right?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1you are correct, and no i didn't say e = x

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1not sure where you got that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)
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