anonymous
  • anonymous
question inside :)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
this is the question, in case my handwriting/drawing is hard to see :P
anonymous
  • anonymous
answer choices A,B,C,D from top to bottom :)

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anonymous
  • anonymous
5x
anonymous
  • anonymous
how'd u get that? :O
anonymous
  • anonymous
im not quite sure if i am understanding this right, but did u just make the 5x not an exponent, so that takes out the ln, so you get e=5x ?? idk is that right?
jim_thompson5910
  • jim_thompson5910
ln is a natural log which 'undoes' the exponential function with 'e' as a base so basically ln(e^x) = x and e^[ ln(x) ] = x which tells you that f(x) = ln(x) and g(x) = e^x are inverse functions
anonymous
  • anonymous
okay, wait so my answer is ln(x) ? or is it ln(5x) ?
jim_thompson5910
  • jim_thompson5910
no i'm just saying in general
anonymous
  • anonymous
wait scratch that... there is no ln(5x) haha my bad... or is it just 5x ?
anonymous
  • anonymous
ohhh okay :P i see
jim_thompson5910
  • jim_thompson5910
in my example, replace each 'x' with '5x'
anonymous
  • anonymous
okay :) so my answer is B. 5x because of that? since e=x ? and x = 5x ?
anonymous
  • anonymous
is that right? since u said e=x right?
jim_thompson5910
  • jim_thompson5910
you are correct, and no i didn't say e = x
jim_thompson5910
  • jim_thompson5910
not sure where you got that
anonymous
  • anonymous
oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)
jim_thompson5910
  • jim_thompson5910
i gotcha
anonymous
  • anonymous
oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)

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