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iheartfood

  • 3 years ago

question inside :)

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  1. iheartfood
    • 3 years ago
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    |dw:1353461289646:dw|

  2. iheartfood
    • 3 years ago
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    this is the question, in case my handwriting/drawing is hard to see :P

  3. iheartfood
    • 3 years ago
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    answer choices A,B,C,D from top to bottom :)

  4. matricked
    • 3 years ago
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    5x

  5. iheartfood
    • 3 years ago
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    how'd u get that? :O

  6. iheartfood
    • 3 years ago
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    im not quite sure if i am understanding this right, but did u just make the 5x not an exponent, so that takes out the ln, so you get e=5x ?? idk is that right?

  7. jim_thompson5910
    • 3 years ago
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    ln is a natural log which 'undoes' the exponential function with 'e' as a base so basically ln(e^x) = x and e^[ ln(x) ] = x which tells you that f(x) = ln(x) and g(x) = e^x are inverse functions

  8. iheartfood
    • 3 years ago
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    okay, wait so my answer is ln(x) ? or is it ln(5x) ?

  9. jim_thompson5910
    • 3 years ago
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    no i'm just saying in general

  10. iheartfood
    • 3 years ago
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    wait scratch that... there is no ln(5x) haha my bad... or is it just 5x ?

  11. iheartfood
    • 3 years ago
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    ohhh okay :P i see

  12. jim_thompson5910
    • 3 years ago
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    in my example, replace each 'x' with '5x'

  13. iheartfood
    • 3 years ago
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    okay :) so my answer is B. 5x because of that? since e=x ? and x = 5x ?

  14. iheartfood
    • 3 years ago
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    is that right? since u said e=x right?

  15. jim_thompson5910
    • 3 years ago
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    you are correct, and no i didn't say e = x

  16. jim_thompson5910
    • 3 years ago
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    not sure where you got that

  17. iheartfood
    • 3 years ago
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    oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)

  18. jim_thompson5910
    • 3 years ago
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    i gotcha

  19. iheartfood
    • 3 years ago
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    oops sorry! i meant this: e^[ ln(x) ] = x lol :P and okay great!! thanks!! :)

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