iheartfood
question inside!! :)



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iheartfood
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dw:1353462316419:dw

iheartfood
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answer choices A,B,C,D from top to bottom :)

jim_thompson5910
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here are the log rules you will use


iheartfood
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kk :)

jim_thompson5910
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use rule #1 to break up the expression to get
log(10^5) + log(x^3)

jim_thompson5910
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what rule is used next?

iheartfood
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umm, idk rule #2?

jim_thompson5910
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read the rules carefully

iheartfood
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sorry rule #1? cuz its + ?

jim_thompson5910
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we used rule 1 to get log(10^5) + log(x^3)

iheartfood
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ohhh then idk :( I'm confused :(

jim_thompson5910
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read the rules again and look at the examples

iheartfood
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okay so i am looking for the rule that solves log(10^5) + log(x^3) ??

jim_thompson5910
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you're looking for a rule that can simplify that yes

iheartfood
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okay so do i use rule #3??

iheartfood
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idk, is that right? rule 3?

jim_thompson5910
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yep, that allows you to pull down the exponents

iheartfood
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okay so how do i solve from there? I'm still a bit lost :(

jim_thompson5910
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ex:
rule 3 says we can go from log(10^5) to 5*log(10)

iheartfood
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ohh okay so i get this?
log(10^5) + log(x^3)
= 5log(10) + 3log(x)
??

jim_thompson5910
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keep going

iheartfood
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which then =5+3log(x)
so my answer is D??
is that right? :O

jim_thompson5910
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the log of 10 is 1 (since log is default base 10)


iheartfood
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okay so if i have 6log(10) my answer is 6?

iheartfood
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and yay!! :)


iheartfood
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kk thanks!!

iheartfood
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kk thanks!!