anonymous
  • anonymous
question inside!! :)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1353462316419:dw|
anonymous
  • anonymous
answer choices A,B,C,D from top to bottom :)
jim_thompson5910
  • jim_thompson5910
here are the log rules you will use

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
http://www.purplemath.com/modules/logrules.htm
anonymous
  • anonymous
kk :)
jim_thompson5910
  • jim_thompson5910
use rule #1 to break up the expression to get log(10^5) + log(x^3)
jim_thompson5910
  • jim_thompson5910
what rule is used next?
anonymous
  • anonymous
umm, idk rule #2?
jim_thompson5910
  • jim_thompson5910
read the rules carefully
anonymous
  • anonymous
sorry rule #1? cuz its + ?
jim_thompson5910
  • jim_thompson5910
we used rule 1 to get log(10^5) + log(x^3)
anonymous
  • anonymous
ohhh then idk :( I'm confused :(
jim_thompson5910
  • jim_thompson5910
read the rules again and look at the examples
anonymous
  • anonymous
okay so i am looking for the rule that solves log(10^5) + log(x^3) ??
jim_thompson5910
  • jim_thompson5910
you're looking for a rule that can simplify that yes
anonymous
  • anonymous
okay so do i use rule #3??
anonymous
  • anonymous
idk, is that right? rule 3?
jim_thompson5910
  • jim_thompson5910
yep, that allows you to pull down the exponents
anonymous
  • anonymous
okay so how do i solve from there? I'm still a bit lost :(
jim_thompson5910
  • jim_thompson5910
ex: rule 3 says we can go from log(10^5) to 5*log(10)
anonymous
  • anonymous
ohh okay so i get this? log(10^5) + log(x^3) = 5log(10) + 3log(x) ??
jim_thompson5910
  • jim_thompson5910
keep going
anonymous
  • anonymous
which then =5+3log(x) so my answer is D?? is that right? :O
jim_thompson5910
  • jim_thompson5910
the log of 10 is 1 (since log is default base 10)
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
okay so if i have 6log(10) my answer is 6?
anonymous
  • anonymous
and yay!! :)
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
kk thanks!!
anonymous
  • anonymous
kk thanks!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.