bmxrider
Only one question I cannot figue out. can someone help please.
What are the solutions?
1/2x^2+ 2x + 3 =0
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freakeo98
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combine like terms
freakeo98
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subtract 3 from both sides
bmxrider
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what like terms, sorry I am having a lot of problems with this.
freakeo98
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lol dude its ok, equations can be confusing to some
freakeo98
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\[\frac{ 1 }{ 2 }x^2+2x+3=0 thats what ur starting out with\]
freakeo98
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thats what ur starting with *
bmxrider
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right. Than you want to get the three to the other side right.
freakeo98
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u can do that first. the thing with equations is that there is no direct way of solving it. there r many ways. just make sure what ever u are doing, make sure it mathimatically makes sense
bmxrider
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1/2^2+2x=-3
freakeo98
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good, now simplify 1/2^x+2x
bmxrider
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here is my problem and were I am stuck. Should I try and get rid of the 1/2?
freakeo98
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do u have a calculator?
bmxrider
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yes
freakeo98
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ok good
freakeo98
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square the half
bmxrider
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lost me again. Sorry.
freakeo98
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lol its ok. do u have a graphing calculator?
bmxrider
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no
freakeo98
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scientific?
bmxrider
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yes
freakeo98
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ok. put 1 divided by 2 and square it
freakeo98
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it should be 1/2^2
freakeo98
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there should be a calculator online
bmxrider
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0.25
freakeo98
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which is 1/4
bmxrider
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I really need help on this to finish a test! last question.
CliffSedge
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@freak098 , you clearly do not understand the question - none of what you said is valid here.
CliffSedge
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This is a quadratic equation, and doesn't look factorable at first glance. Quadratic formula is your best option.
bmxrider
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I think you use the quadratic formula. Am I correct?
bmxrider
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yes
CliffSedge
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Quadratic formula always works, so is typically the weapon of choice in this situation.
A good way to start though, is to multiply everything by 2 first to clear the fraction.
bmxrider
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2(1/2x^2+2x+3=0(2)
x^2+4x+6=0
correct?
CliffSedge
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Yeah, then use the QF on that.
bmxrider
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ok. I think I got it now. It was the 1/2 I was confused on. Thank you very much.
CliffSedge
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No problem. When I tried it, I was getting non-real answers, so don't be surprised about that.
bmxrider
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ok. I will try it