Only one question I cannot figue out. can someone help please.
What are the solutions?
1/2x^2+ 2x + 3 =0

- anonymous

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- anonymous

combine like terms

- anonymous

subtract 3 from both sides

- anonymous

what like terms, sorry I am having a lot of problems with this.

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## More answers

- anonymous

lol dude its ok, equations can be confusing to some

- anonymous

\[\frac{ 1 }{ 2 }x^2+2x+3=0 thats what ur starting out with\]

- anonymous

thats what ur starting with *

- anonymous

right. Than you want to get the three to the other side right.

- anonymous

u can do that first. the thing with equations is that there is no direct way of solving it. there r many ways. just make sure what ever u are doing, make sure it mathimatically makes sense

- anonymous

1/2^2+2x=-3

- anonymous

good, now simplify 1/2^x+2x

- anonymous

here is my problem and were I am stuck. Should I try and get rid of the 1/2?

- anonymous

do u have a calculator?

- anonymous

yes

- anonymous

ok good

- anonymous

square the half

- anonymous

lost me again. Sorry.

- anonymous

lol its ok. do u have a graphing calculator?

- anonymous

no

- anonymous

scientific?

- anonymous

yes

- anonymous

ok. put 1 divided by 2 and square it

- anonymous

it should be 1/2^2

- anonymous

there should be a calculator online

- anonymous

0.25

- anonymous

which is 1/4

- anonymous

I really need help on this to finish a test! last question.

- anonymous

@freak098 , you clearly do not understand the question - none of what you said is valid here.

- anonymous

This is a quadratic equation, and doesn't look factorable at first glance. Quadratic formula is your best option.

- anonymous

I think you use the quadratic formula. Am I correct?

- anonymous

yes

- anonymous

Quadratic formula always works, so is typically the weapon of choice in this situation.
A good way to start though, is to multiply everything by 2 first to clear the fraction.

- anonymous

2(1/2x^2+2x+3=0(2)
x^2+4x+6=0
correct?

- anonymous

Yeah, then use the QF on that.

- anonymous

ok. I think I got it now. It was the 1/2 I was confused on. Thank you very much.

- anonymous

No problem. When I tried it, I was getting non-real answers, so don't be surprised about that.

- anonymous

ok. I will try it

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