## anonymous 3 years ago Only one question I cannot figue out. can someone help please. What are the solutions? 1/2x^2+ 2x + 3 =0

1. anonymous

combine like terms

2. anonymous

subtract 3 from both sides

3. anonymous

what like terms, sorry I am having a lot of problems with this.

4. anonymous

lol dude its ok, equations can be confusing to some

5. anonymous

$\frac{ 1 }{ 2 }x^2+2x+3=0 thats what ur starting out with$

6. anonymous

thats what ur starting with *

7. anonymous

right. Than you want to get the three to the other side right.

8. anonymous

u can do that first. the thing with equations is that there is no direct way of solving it. there r many ways. just make sure what ever u are doing, make sure it mathimatically makes sense

9. anonymous

1/2^2+2x=-3

10. anonymous

good, now simplify 1/2^x+2x

11. anonymous

here is my problem and were I am stuck. Should I try and get rid of the 1/2?

12. anonymous

do u have a calculator?

13. anonymous

yes

14. anonymous

ok good

15. anonymous

square the half

16. anonymous

lost me again. Sorry.

17. anonymous

lol its ok. do u have a graphing calculator?

18. anonymous

no

19. anonymous

scientific?

20. anonymous

yes

21. anonymous

ok. put 1 divided by 2 and square it

22. anonymous

it should be 1/2^2

23. anonymous

there should be a calculator online

24. anonymous

0.25

25. anonymous

which is 1/4

26. anonymous

I really need help on this to finish a test! last question.

27. anonymous

@freak098 , you clearly do not understand the question - none of what you said is valid here.

28. anonymous

This is a quadratic equation, and doesn't look factorable at first glance. Quadratic formula is your best option.

29. anonymous

I think you use the quadratic formula. Am I correct?

30. anonymous

yes

31. anonymous

Quadratic formula always works, so is typically the weapon of choice in this situation. A good way to start though, is to multiply everything by 2 first to clear the fraction.

32. anonymous

2(1/2x^2+2x+3=0(2) x^2+4x+6=0 correct?

33. anonymous

Yeah, then use the QF on that.

34. anonymous

ok. I think I got it now. It was the 1/2 I was confused on. Thank you very much.

35. anonymous

No problem. When I tried it, I was getting non-real answers, so don't be surprised about that.

36. anonymous

ok. I will try it