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- anonymous

Help needed??

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- anonymous

Help needed??

- jamiebookeater

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- anonymous

Find the total area of all shaded rectangles. This is about Polynomials have no idea where to start

- anonymous

Step by step if possible

- allank

What you want to do first is identify the rectangles. I spot two. Do you?

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- anonymous

I am so confused right now

- anonymous

I am confused and i do not even get my question i post

- anonymous

I completely understand

- anonymous

looks like they are all shaded

- anonymous

since they are all shaded, and since you have a square, the area is the square of the side
the length of the side is \(3x+4\) so the total area is \((3x+4)^2\)

- anonymous

ok

- anonymous

How did you get that?

- anonymous

by looking across the top and adding the two lengths. one is \(3x\) the other is \(4\) so the total length is \(3x+4\)

- anonymous

and therefore the total area is \((3x+4)^2\)

- anonymous

See the book is horrible at explaining how to do this, what does this have to do with Polynomials

- anonymous

the other answer is the area of the large square, which is \(3x\times 3x=9x^2\) plus the area of the small square which is \(4\times 4=16\) plus the area of the two reactangles, each of which is \(3x\times 4=12x\)
when you add these you get
\[9x^2+12x+12x+16=9x^2+24x+16\]

- anonymous

they are trying to get you to see by making a square, that
\[(3x+4)^2=9x^2+24x+16\]

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