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andjie

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  • one year ago
  • one year ago

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  1. andjie
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    Find the total area of all shaded rectangles. This is about Polynomials have no idea where to start

    • one year ago
  2. andjie
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    Step by step if possible

    • one year ago
  3. allank
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    What you want to do first is identify the rectangles. I spot two. Do you?

    • one year ago
  4. andjie
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    I am so confused right now

    • one year ago
  5. Emilyggarza
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    I am confused and i do not even get my question i post

    • one year ago
  6. andjie
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    I completely understand

    • one year ago
  7. satellite73
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    looks like they are all shaded

    • one year ago
  8. satellite73
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    since they are all shaded, and since you have a square, the area is the square of the side the length of the side is \(3x+4\) so the total area is \((3x+4)^2\)

    • one year ago
  9. andjie
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    ok

    • one year ago
  10. andjie
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    How did you get that?

    • one year ago
  11. satellite73
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    by looking across the top and adding the two lengths. one is \(3x\) the other is \(4\) so the total length is \(3x+4\)

    • one year ago
  12. satellite73
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    and therefore the total area is \((3x+4)^2\)

    • one year ago
  13. andjie
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    See the book is horrible at explaining how to do this, what does this have to do with Polynomials

    • one year ago
  14. satellite73
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    the other answer is the area of the large square, which is \(3x\times 3x=9x^2\) plus the area of the small square which is \(4\times 4=16\) plus the area of the two reactangles, each of which is \(3x\times 4=12x\) when you add these you get \[9x^2+12x+12x+16=9x^2+24x+16\]

    • one year ago
  15. satellite73
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    they are trying to get you to see by making a square, that \[(3x+4)^2=9x^2+24x+16\]

    • one year ago
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