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andjie

  • 3 years ago

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  1. andjie
    • 3 years ago
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    Find the total area of all shaded rectangles. This is about Polynomials have no idea where to start

  2. andjie
    • 3 years ago
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    Step by step if possible

  3. allank
    • 3 years ago
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    What you want to do first is identify the rectangles. I spot two. Do you?

  4. andjie
    • 3 years ago
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    I am so confused right now

  5. Emilyggarza
    • 3 years ago
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    I am confused and i do not even get my question i post

  6. andjie
    • 3 years ago
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    I completely understand

  7. anonymous
    • 3 years ago
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    looks like they are all shaded

  8. anonymous
    • 3 years ago
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    since they are all shaded, and since you have a square, the area is the square of the side the length of the side is \(3x+4\) so the total area is \((3x+4)^2\)

  9. andjie
    • 3 years ago
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    ok

  10. andjie
    • 3 years ago
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    How did you get that?

  11. anonymous
    • 3 years ago
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    by looking across the top and adding the two lengths. one is \(3x\) the other is \(4\) so the total length is \(3x+4\)

  12. anonymous
    • 3 years ago
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    and therefore the total area is \((3x+4)^2\)

  13. andjie
    • 3 years ago
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    See the book is horrible at explaining how to do this, what does this have to do with Polynomials

  14. anonymous
    • 3 years ago
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    the other answer is the area of the large square, which is \(3x\times 3x=9x^2\) plus the area of the small square which is \(4\times 4=16\) plus the area of the two reactangles, each of which is \(3x\times 4=12x\) when you add these you get \[9x^2+12x+12x+16=9x^2+24x+16\]

  15. anonymous
    • 3 years ago
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    they are trying to get you to see by making a square, that \[(3x+4)^2=9x^2+24x+16\]

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