anonymous
  • anonymous
Help needed??
Algebra
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Find the total area of all shaded rectangles. This is about Polynomials have no idea where to start
anonymous
  • anonymous
Step by step if possible
allank
  • allank
What you want to do first is identify the rectangles. I spot two. Do you?

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anonymous
  • anonymous
I am so confused right now
anonymous
  • anonymous
I am confused and i do not even get my question i post
anonymous
  • anonymous
I completely understand
anonymous
  • anonymous
looks like they are all shaded
anonymous
  • anonymous
since they are all shaded, and since you have a square, the area is the square of the side the length of the side is \(3x+4\) so the total area is \((3x+4)^2\)
anonymous
  • anonymous
ok
anonymous
  • anonymous
How did you get that?
anonymous
  • anonymous
by looking across the top and adding the two lengths. one is \(3x\) the other is \(4\) so the total length is \(3x+4\)
anonymous
  • anonymous
and therefore the total area is \((3x+4)^2\)
anonymous
  • anonymous
See the book is horrible at explaining how to do this, what does this have to do with Polynomials
anonymous
  • anonymous
the other answer is the area of the large square, which is \(3x\times 3x=9x^2\) plus the area of the small square which is \(4\times 4=16\) plus the area of the two reactangles, each of which is \(3x\times 4=12x\) when you add these you get \[9x^2+12x+12x+16=9x^2+24x+16\]
anonymous
  • anonymous
they are trying to get you to see by making a square, that \[(3x+4)^2=9x^2+24x+16\]

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