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Unclear how to proceed. What is the first term, \(\cos(2x)\) or \(\cos^{2}(x)\)?

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cos \[\cos^{2}x\]

That is where I got stuck I am not sure what to do after factoring

what each of the equal?

them*

tkhunny your explanations are more complex than the problem itself :)

cos x+1(0)=0 I am not sure

I do... but if cos(x)=-1 wouldn't [x=\pi\]

\[x=\]

x=pi*

anyway I got it ... thanks for the help!

Awesome. How did I do that?! Right you are. \(x = \pi + 2k\pi\)

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