Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

sabika13 Group Title

solve for x in the given interval sqrt2sinx+tanx=0 (-pi,pi)

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    even i'm waiting for someone to answer your question... eager to know ...

    • 2 years ago
  2. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    sabika only sin x is underroot or whole?

    • 2 years ago
  3. sabika13 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    sqrt2sinx ***

    • 2 years ago
  4. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    sqrsinx + tanx = 0 sqrsinx = - tanx sinx = tan^2x squaring both sides 1 = 1/cosx dividing both sides by sinx cosx = 1 crossmultiplying x = 0 i am not sure ... .. but i just tried i am also learning trigonometry

    • 2 years ago
  5. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @sabika13 check my answer... i think i am so right.... tell me

    • 2 years ago
  6. sabika13 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry it was sqrt 2 sinx

    • 2 years ago
  7. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    1st time in my life i had tried such trig equ omg omg.... :( :(

    • 2 years ago
  8. rizwan_uet Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    sqrt 2sinx + tanx = 0 sqrt 2sinx = -tanx squaring both sides we get 2sinx = tan^2x 2 = sinx/cos^2x

    • 2 years ago
  9. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    sabika, before ppl can help you, they need to understand your question clearly. even now your question is vague... not clear..... is it sqrt2(sin x ) or sqrt(2sin x ) ?

    • 2 years ago
  10. sabika13 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @rizwan_uet can you keep going or are you stuck? @jatinbansalhot its sqrt2sinx

    • 2 years ago
  11. rizwan_uet Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    2cos*2x=sinx 2(1-sin^2x) = sinx 2-2sin^x -sinx = 0 sinx(-2sinx -1) = -2

    • 2 years ago
  12. rizwan_uet Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i m trying......

    • 2 years ago
  13. sabika13 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    -2sin^2x-sinx +2 = 0 is good! thanks!!

    • 2 years ago
  14. rizwan_uet Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    its right or not???

    • 2 years ago
  15. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    hhahahahaahahahahahahha... i'm not going to solve her problem... she is not clear...

    • 2 years ago
  16. sabika13 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ? i dont know if its right.. thats why im asking a question..

    • 2 years ago
  17. rizwan_uet Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    up to this point i did my best but the rest is difficuilt for me sorry..

    • 2 years ago
  18. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    x = pi / 4, -pi / 4 .... m i right

    • 2 years ago
  19. matricked Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    sqrt 2sinx + tanx = 0 sqrt 2sinx = -tanx after squaring both sides we get 2sinx = tan^2x or sinx(2-sinx/(cos^2x))=0 then sinx=0 or x=0,pi,-pi (one part ) the other part may can be obtained from (2-sinx/(cos^2x))=0

    • 2 years ago
  20. sabika13 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    how did you go from 2sinx=tan^2x to sinx(2-sinx/cos^2x0 =0 ?

    • 2 years ago
  21. matricked Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    use tanx=sinx/cosx

    • 2 years ago
  22. sabika13 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah so sin^2x/cos^2x =2sinx 2sinxcos^2x=sinx^2 2sinx(1-sin^2x)=sin^2x ... am i doing it right?

    • 2 years ago
  23. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    2sinx cos^2x = sin^2x i have taken this statement from you 2sinx ( 1 - sin^2 ) = sin^2x 2sinx - 2sin^3 =sin^2x 2sinx - 2sin^3 - sin^2x = 0 2sin^3 + sin^2x - 2sinx = 0 sinx( 2sin^2 + sinx - 2 ) = 0

    • 2 years ago
  24. jatinbansalhot Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @sabika13 did my work help u? i want to know ..... do tell me

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.