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even i'm waiting for someone to answer your question... eager to know ...

sabika only sin x is underroot or whole?

sqrt2sinx ***

sorry it was sqrt 2 sinx

1st time in my life i had tried such trig equ omg omg.... :( :(

sqrt 2sinx + tanx = 0
sqrt 2sinx = -tanx
squaring both sides we get
2sinx = tan^2x
2 = sinx/cos^2x

@rizwan_uet can you keep going or are you stuck?
@jatinbansalhot its sqrt2sinx

2cos*2x=sinx
2(1-sin^2x) = sinx
2-2sin^x -sinx = 0
sinx(-2sinx -1) = -2

i m trying......

-2sin^2x-sinx +2 = 0 is good! thanks!!

its right or not???

hhahahahaahahahahahahha... i'm not going to solve her problem... she is not clear...

? i dont know if its right.. thats why im asking a question..

up to this point i did my best but the rest is difficuilt for me sorry..

x = pi / 4, -pi / 4 .... m i right

how did you go from 2sinx=tan^2x to sinx(2-sinx/cos^2x0 =0 ?

use tanx=sinx/cosx

yeah so sin^2x/cos^2x =2sinx
2sinxcos^2x=sinx^2
2sinx(1-sin^2x)=sin^2x
... am i doing it right?