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anonymous
 4 years ago
solve for x in the given interval sqrt2sinx+tanx=0 (pi,pi)
anonymous
 4 years ago
solve for x in the given interval sqrt2sinx+tanx=0 (pi,pi)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0even i'm waiting for someone to answer your question... eager to know ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sabika only sin x is underroot or whole?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sqrsinx + tanx = 0 sqrsinx =  tanx sinx = tan^2x squaring both sides 1 = 1/cosx dividing both sides by sinx cosx = 1 crossmultiplying x = 0 i am not sure ... .. but i just tried i am also learning trigonometry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@sabika13 check my answer... i think i am so right.... tell me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry it was sqrt 2 sinx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01st time in my life i had tried such trig equ omg omg.... :( :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sqrt 2sinx + tanx = 0 sqrt 2sinx = tanx squaring both sides we get 2sinx = tan^2x 2 = sinx/cos^2x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sabika, before ppl can help you, they need to understand your question clearly. even now your question is vague... not clear..... is it sqrt2(sin x ) or sqrt(2sin x ) ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@rizwan_uet can you keep going or are you stuck? @jatinbansalhot its sqrt2sinx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02cos*2x=sinx 2(1sin^2x) = sinx 22sin^x sinx = 0 sinx(2sinx 1) = 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02sin^2xsinx +2 = 0 is good! thanks!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hhahahahaahahahahahahha... i'm not going to solve her problem... she is not clear...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0? i dont know if its right.. thats why im asking a question..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0up to this point i did my best but the rest is difficuilt for me sorry..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x = pi / 4, pi / 4 .... m i right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sqrt 2sinx + tanx = 0 sqrt 2sinx = tanx after squaring both sides we get 2sinx = tan^2x or sinx(2sinx/(cos^2x))=0 then sinx=0 or x=0,pi,pi (one part ) the other part may can be obtained from (2sinx/(cos^2x))=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you go from 2sinx=tan^2x to sinx(2sinx/cos^2x0 =0 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah so sin^2x/cos^2x =2sinx 2sinxcos^2x=sinx^2 2sinx(1sin^2x)=sin^2x ... am i doing it right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02sinx cos^2x = sin^2x i have taken this statement from you 2sinx ( 1  sin^2 ) = sin^2x 2sinx  2sin^3 =sin^2x 2sinx  2sin^3  sin^2x = 0 2sin^3 + sin^2x  2sinx = 0 sinx( 2sin^2 + sinx  2 ) = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@sabika13 did my work help u? i want to know ..... do tell me
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