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## anonymous 4 years ago solve for x in the given interval 2tanx=secx (-2pi,0)

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1. anonymous

$$\large 2tanx=secx$$ $$\large 2\frac{sinx}{cosx}=\frac{1}{cosx}$$ $$\large \frac{2sinx}{cosx}=\frac{1}{cosx}$$ $$\large 2sinx=1$$ numerators must be equal $$\large sinx=\frac{1}{2}$$ Can you do the rest from here?

2. anonymous

Yess thank you :D

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