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sabika13
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solve for x in the given interval
2tanx=secx (2pi,0)
 one year ago
 one year ago
sabika13 Group Title
solve for x in the given interval 2tanx=secx (2pi,0)
 one year ago
 one year ago

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ByteMe Group TitleBest ResponseYou've already chosen the best response.0
\(\large 2tanx=secx \) \(\large 2\frac{sinx}{cosx}=\frac{1}{cosx} \) \(\large \frac{2sinx}{cosx}=\frac{1}{cosx} \) \(\large 2sinx=1 \) numerators must be equal \(\large sinx=\frac{1}{2} \) Can you do the rest from here?
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
Yess thank you :D
 one year ago
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