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sabika13

  • 3 years ago

solve for x in the given interval 2tanx=secx (-2pi,0)

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  1. ByteMe
    • 3 years ago
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    \(\large 2tanx=secx \) \(\large 2\frac{sinx}{cosx}=\frac{1}{cosx} \) \(\large \frac{2sinx}{cosx}=\frac{1}{cosx} \) \(\large 2sinx=1 \) numerators must be equal \(\large sinx=\frac{1}{2} \) Can you do the rest from here?

  2. sabika13
    • 3 years ago
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    Yess thank you :D

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