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Sona Group Title

please help 6tanθ−6cotθ=0

  • one year ago
  • one year ago

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  1. ByteMe Group Title
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    divide both sides by 6 so your equation is now: tanx - cotx = 0 let's use "x" instead of "theta"... easier to type...

    • one year ago
  2. Sona Group Title
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    ok....tanx-cotx=0 then wat?

    • one year ago
  3. ByteMe Group Title
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    try writing the equation in terms of only sin and cos....

    • one year ago
  4. Sona Group Title
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    ok is 45 135 225 n 315 the solutions?

    • one year ago
  5. ByteMe Group Title
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    idk... i didn't solve.... yet.... maybe these guys will...

    • one year ago
  6. ChmE Group Title
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    \[\tan \theta = \cot \theta\]\[\frac{ \sin \theta }{ \cos \theta }=\frac{ \cos \theta }{ \sin \theta }\]\[\sin^2 \theta=\cos^2 \theta\]

    • one year ago
  7. ChmE Group Title
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    \[\sin \theta = \cos \theta\]they only equal the same value at 2 different degrees ( or radians). Are you familiar with the unit circle

    • one year ago
  8. Sona Group Title
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    yes

    • one year ago
  9. ChmE Group Title
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    One answer will be in quadrant 1 the other in 3.

    • one year ago
  10. Sona Group Title
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    ok i just got it thank u all!

    • one year ago
  11. ChmE Group Title
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    hold on. i think you were right above

    • one year ago
  12. ChmE Group Title
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    if each term is squared then there wil be no negative numbers

    • one year ago
  13. ChmE Group Title
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    and you will have 4 solutions

    • one year ago
  14. ChmE Group Title
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    45, 135, 225, 315

    • one year ago
  15. Sona Group Title
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    yup

    • one year ago
  16. ChmE Group Title
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    Good job

    • one year ago
  17. Sona Group Title
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    thank u tho

    • one year ago
  18. tamtoan Group Title
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    when you have (sin^2)(x) = (cos^2)(x) ....use (cos^2)(x) = 1 - (sin^2)(x) and substitute in, you then can solve because now you only have one variable ... ** i don't know to to write in the form like chme does, or else, it would look much easier.

    • one year ago
  19. ChmE Group Title
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    its the equation button below the this text field.

    • one year ago
  20. tamtoan Group Title
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    i got it, thanks @chme very much

    • one year ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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