anonymous
  • anonymous
please help 6tanθ−6cotθ=0
Trigonometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
divide both sides by 6 so your equation is now: tanx - cotx = 0 let's use "x" instead of "theta"... easier to type...
anonymous
  • anonymous
ok....tanx-cotx=0 then wat?
anonymous
  • anonymous
try writing the equation in terms of only sin and cos....

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anonymous
  • anonymous
ok is 45 135 225 n 315 the solutions?
anonymous
  • anonymous
idk... i didn't solve.... yet.... maybe these guys will...
anonymous
  • anonymous
\[\tan \theta = \cot \theta\]\[\frac{ \sin \theta }{ \cos \theta }=\frac{ \cos \theta }{ \sin \theta }\]\[\sin^2 \theta=\cos^2 \theta\]
anonymous
  • anonymous
\[\sin \theta = \cos \theta\]they only equal the same value at 2 different degrees ( or radians). Are you familiar with the unit circle
anonymous
  • anonymous
yes
anonymous
  • anonymous
One answer will be in quadrant 1 the other in 3.
anonymous
  • anonymous
ok i just got it thank u all!
anonymous
  • anonymous
hold on. i think you were right above
anonymous
  • anonymous
if each term is squared then there wil be no negative numbers
anonymous
  • anonymous
and you will have 4 solutions
anonymous
  • anonymous
45, 135, 225, 315
anonymous
  • anonymous
yup
anonymous
  • anonymous
Good job
anonymous
  • anonymous
thank u tho
tamtoan
  • tamtoan
when you have (sin^2)(x) = (cos^2)(x) ....use (cos^2)(x) = 1 - (sin^2)(x) and substitute in, you then can solve because now you only have one variable ... ** i don't know to to write in the form like chme does, or else, it would look much easier.
anonymous
  • anonymous
its the equation button below the this text field.
tamtoan
  • tamtoan
i got it, thanks @chme very much

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