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please help 6tanθ−6cotθ=0

Trigonometry
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divide both sides by 6 so your equation is now: tanx - cotx = 0 let's use "x" instead of "theta"... easier to type...
ok....tanx-cotx=0 then wat?
try writing the equation in terms of only sin and cos....

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Other answers:

ok is 45 135 225 n 315 the solutions?
idk... i didn't solve.... yet.... maybe these guys will...
\[\tan \theta = \cot \theta\]\[\frac{ \sin \theta }{ \cos \theta }=\frac{ \cos \theta }{ \sin \theta }\]\[\sin^2 \theta=\cos^2 \theta\]
\[\sin \theta = \cos \theta\]they only equal the same value at 2 different degrees ( or radians). Are you familiar with the unit circle
yes
One answer will be in quadrant 1 the other in 3.
ok i just got it thank u all!
hold on. i think you were right above
if each term is squared then there wil be no negative numbers
and you will have 4 solutions
45, 135, 225, 315
yup
Good job
thank u tho
when you have (sin^2)(x) = (cos^2)(x) ....use (cos^2)(x) = 1 - (sin^2)(x) and substitute in, you then can solve because now you only have one variable ... ** i don't know to to write in the form like chme does, or else, it would look much easier.
its the equation button below the this text field.
i got it, thanks @chme very much

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