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Sona

  • 3 years ago

please help 6tanθ−6cotθ=0

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  1. ByteMe
    • 3 years ago
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    divide both sides by 6 so your equation is now: tanx - cotx = 0 let's use "x" instead of "theta"... easier to type...

  2. Sona
    • 3 years ago
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    ok....tanx-cotx=0 then wat?

  3. ByteMe
    • 3 years ago
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    try writing the equation in terms of only sin and cos....

  4. Sona
    • 3 years ago
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    ok is 45 135 225 n 315 the solutions?

  5. ByteMe
    • 3 years ago
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    idk... i didn't solve.... yet.... maybe these guys will...

  6. ChmE
    • 3 years ago
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    \[\tan \theta = \cot \theta\]\[\frac{ \sin \theta }{ \cos \theta }=\frac{ \cos \theta }{ \sin \theta }\]\[\sin^2 \theta=\cos^2 \theta\]

  7. ChmE
    • 3 years ago
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    \[\sin \theta = \cos \theta\]they only equal the same value at 2 different degrees ( or radians). Are you familiar with the unit circle

  8. Sona
    • 3 years ago
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    yes

  9. ChmE
    • 3 years ago
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    One answer will be in quadrant 1 the other in 3.

  10. Sona
    • 3 years ago
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    ok i just got it thank u all!

  11. ChmE
    • 3 years ago
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    hold on. i think you were right above

  12. ChmE
    • 3 years ago
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    if each term is squared then there wil be no negative numbers

  13. ChmE
    • 3 years ago
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    and you will have 4 solutions

  14. ChmE
    • 3 years ago
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    45, 135, 225, 315

  15. Sona
    • 3 years ago
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    yup

  16. ChmE
    • 3 years ago
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    Good job

  17. Sona
    • 3 years ago
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    thank u tho

  18. tamtoan
    • 3 years ago
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    when you have (sin^2)(x) = (cos^2)(x) ....use (cos^2)(x) = 1 - (sin^2)(x) and substitute in, you then can solve because now you only have one variable ... ** i don't know to to write in the form like chme does, or else, it would look much easier.

  19. ChmE
    • 3 years ago
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    its the equation button below the this text field.

  20. tamtoan
    • 3 years ago
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    i got it, thanks @chme very much

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