Sona
please help
6tanθ−6cotθ=0
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ByteMe
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divide both sides by 6 so your equation is now: tanx - cotx = 0
let's use "x" instead of "theta"... easier to type...
Sona
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ok....tanx-cotx=0 then wat?
ByteMe
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try writing the equation in terms of only sin and cos....
Sona
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ok is 45 135 225 n 315 the solutions?
ByteMe
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idk... i didn't solve.... yet....
maybe these guys will...
ChmE
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\[\tan \theta = \cot \theta\]\[\frac{ \sin \theta }{ \cos \theta }=\frac{ \cos \theta }{ \sin \theta }\]\[\sin^2 \theta=\cos^2 \theta\]
ChmE
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\[\sin \theta = \cos \theta\]they only equal the same value at 2 different degrees ( or radians). Are you familiar with the unit circle
Sona
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yes
ChmE
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One answer will be in quadrant 1 the other in 3.
Sona
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ok i just got it thank u all!
ChmE
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hold on. i think you were right above
ChmE
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if each term is squared then there wil be no negative numbers
ChmE
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and you will have 4 solutions
ChmE
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45, 135, 225, 315
Sona
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yup
ChmE
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Good job
Sona
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thank u tho
tamtoan
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when you have (sin^2)(x) = (cos^2)(x) ....use (cos^2)(x) = 1 - (sin^2)(x) and substitute in, you then can solve because now you only have one variable ...
** i don't know to to write in the form like chme does, or else, it would look much easier.
ChmE
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its the equation button below the this text field.
tamtoan
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i got it, thanks @chme very much