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## anonymous 3 years ago please help 6tanθ−6cotθ=0

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1. anonymous

divide both sides by 6 so your equation is now: tanx - cotx = 0 let's use "x" instead of "theta"... easier to type...

2. anonymous

ok....tanx-cotx=0 then wat?

3. anonymous

try writing the equation in terms of only sin and cos....

4. anonymous

ok is 45 135 225 n 315 the solutions?

5. anonymous

idk... i didn't solve.... yet.... maybe these guys will...

6. anonymous

$\tan \theta = \cot \theta$$\frac{ \sin \theta }{ \cos \theta }=\frac{ \cos \theta }{ \sin \theta }$$\sin^2 \theta=\cos^2 \theta$

7. anonymous

$\sin \theta = \cos \theta$they only equal the same value at 2 different degrees ( or radians). Are you familiar with the unit circle

8. anonymous

yes

9. anonymous

One answer will be in quadrant 1 the other in 3.

10. anonymous

ok i just got it thank u all!

11. anonymous

hold on. i think you were right above

12. anonymous

if each term is squared then there wil be no negative numbers

13. anonymous

and you will have 4 solutions

14. anonymous

45, 135, 225, 315

15. anonymous

yup

16. anonymous

Good job

17. anonymous

thank u tho

18. tamtoan

when you have (sin^2)(x) = (cos^2)(x) ....use (cos^2)(x) = 1 - (sin^2)(x) and substitute in, you then can solve because now you only have one variable ... ** i don't know to to write in the form like chme does, or else, it would look much easier.

19. anonymous

its the equation button below the this text field.

20. tamtoan

i got it, thanks @chme very much

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