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can someone explain to me how to find two positive numbers such that the sum of the first and twice the second is 100 and their product is a maximum

Calculus1
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You still there? Do you need help?
yes please!
Do you know calculus?

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Other answers:

well haha i'm in the class right now but not really...
Okay. That's fine.
well are you going to help?(:
Do you want just the answer, or how to get the answer?
how to get it please (:
how to get it please (:
okay.
let x= the first number let y= the second number
so, x+2y=100.
You are trying to maximize the product yz. so let z= the product = to xy
Following so far?
yeah(:
okay, so solve x+2y=100 for x. x=100-2y z=xy z=(100-2y)y z=y(100-2y) z=100y-2y^2
Now, just find the vertex of that graph using -b/2a
Therefore, the first value is 25 and the second value is 50.
Let me simplify this down a bit, because I was writing out my work which may be a bit confusing.
So, you have been told that the sum of the first number, twice the second is 100 (I'll use just x and y this time to make things less confusing) so, x+2y=100.
You are trying to minimize the product, P=xy. So solve the first equation x+2y=100, for x.........x=100-2y. Now substitute this into the product formula ( P=xy)
ohhh wait i get it! thank you!!!! do you have time to help me with another one?(:
P = xy = (100 − 2y)y = 100y − 2y^2
Sure.

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