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reymerXXVIII

  • 2 years ago

In a right triangle, a line perpendicular to the hypotenuse drawn from the midpoint of one of the sides divides the hypotenuse into segments which are 10 cm and 6cm long. Find the lengths of the 2 sides of the triangle.

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  1. Shadowys
    • 2 years ago
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    |dw:1353498576458:dw| use tan theta to get it. Do you need further help?

  2. radar
    • 2 years ago
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    The above drawing is not representative of the problem. The line is supposed to intercept the midpoint of a "side" of the triangle.

  3. radar
    • 2 years ago
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    |dw:1366123536832:dw|

  4. radar
    • 2 years ago
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    Not that I know how to solve it, but I think that may represent the problem.

  5. radar
    • 2 years ago
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    |dw:1366123536832:dw|

  6. Shadowys
    • 2 years ago
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    radar, i don't get your drawing==

  7. radar
    • 2 years ago
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    Problem states a line is drawn perpendicular (right angle) to the hypotenuse to the midpoint of one of the sides of the triangle (not to the mid angle of the vertice)|dw:1366718909433:dw| Does that clear up the drawing (which by the way, was a previous posted drawing which I attempted to modify to comply with the wording of the problem.

  8. Shadowys
    • 2 years ago
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    ah. that cleared that up.

  9. radar
    • 2 years ago
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    I was hoping that someone could solve it. (just for my own curiosity and learning) Could you possibly solve it @Shadowys

  10. Shadowys
    • 2 years ago
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    |dw:1366878774356:dw| cos theta= 6/d = 2d/10 solving it gives d=sqrt 30 the other side can be found by pythagoras theorem

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