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In a right triangle, a line perpendicular to the hypotenuse drawn from the midpoint of one of the sides divides the hypotenuse into segments which are 10 cm and 6cm long. Find the lengths of the 2 sides of the triangle.

Geometry
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|dw:1353498576458:dw| use tan theta to get it. Do you need further help?
The above drawing is not representative of the problem. The line is supposed to intercept the midpoint of a "side" of the triangle.
|dw:1366123536832:dw|

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Other answers:

Not that I know how to solve it, but I think that may represent the problem.
|dw:1366123536832:dw|
radar, i don't get your drawing==
Problem states a line is drawn perpendicular (right angle) to the hypotenuse to the midpoint of one of the sides of the triangle (not to the mid angle of the vertice)|dw:1366718909433:dw| Does that clear up the drawing (which by the way, was a previous posted drawing which I attempted to modify to comply with the wording of the problem.
ah. that cleared that up.
I was hoping that someone could solve it. (just for my own curiosity and learning) Could you possibly solve it @Shadowys
|dw:1366878774356:dw| cos theta= 6/d = 2d/10 solving it gives d=sqrt 30 the other side can be found by pythagoras theorem

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