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mayankdevnani
 3 years ago
A ball is dropped on to the floor from a height of 10 m. It reboundes to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, what is the average acceleration during contact?
a) \[1400 m/s^2\]
b) \[2100 m/s^2\]
c) \[700 m/s^2\]
d) \[2800 m/s^2\]
mayankdevnani
 3 years ago
A ball is dropped on to the floor from a height of 10 m. It reboundes to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, what is the average acceleration during contact? a) \[1400 m/s^2\] b) \[2100 m/s^2\] c) \[700 m/s^2\] d) \[2800 m/s^2\]

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mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2@amistre64 @hba @asnaseer @AccessDenied @jhonyy9 @jazy @ganeshie8

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1The acceleration of a body is defined as the change of its velocity during an interval of time divided by the interval of time. Expressed algebraically, a = (Vo  Vf)/t where a = the acceleration, Vo = the initial velocity, Vf = the final velocity and t = the interval of time.

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1From the basic a = (Vo  Vf) we derive the first as ......................................t ..............................Vf = Vo + at (the acceleration is assumed constant)

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1The second defines the relationship between the distance traveled by a body exposed to a constant acceleration. The distance traveled over an interval of time derives from the product of the average velocity during the time interval and the time interval. The average velocity is (Vo + Vf)/2 and the time interval "t" which yields d = (Vo + Vf)t/2. Substituting the Vf derived above, d = [Vo + (Vo + at)]t/2 resulting in ...............................d = Vo(t) + a(t^2) (quite often, s is used in place of d) ......................................................2

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1The third combines the first two by eliminating the time interval "t". Therefore, a(d) = (Vo  Vf)(Vo + Vf)t = (1/2)(Vf  Vo)(Vf + Vo) resulting in .....................................t.............2 ..............................Vf^2 = Vo^2 + 2ad

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2thnx.... @tictac4456

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1no problem do u go to connexus

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2is it right?? While falling down, initial velocity = 0, final velocity = v, acceleration due to gravity = 9.8 m/s 2 , height = 10 m The velocity of the ball with which it hits the ground can be found using, v 2 = u 2 + 2as => v 2 = 0 + 2×9.8×10 => v = 14 m/s (downward) While it moves up, initial velocity = u, final velocity = 0, acceleration due to gravity = 9.8 m/s2 [this time the velocity and acceleration are oppositely directed so we have the negative sign] , height = 2.5 m The velocity of the ball with which it leaves the ground can be found using, v 2 = u 2 + 2as => 0 = u 2  2×9.8×2.5 => u = 7 m/s (upward) So, Change in velocity = 7 m/s (upward) – 14 m/s (downward) => Δv = 7 m/s + 14 m/s [both in upward direction] => Δv = 21 m/s So, acceleration is, a = Δv/Δt = 21/0.01 = 2100 m/s 2

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2@satellite73 help me:)

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1hey ur work is correct but the answer is wrong

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1oh im srry never mind i didnt see the seconds ur answer is correct

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1im 100% sure its right

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0I agree  your work and answer is correct

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1do ya take entrepuener class

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2what do you mean??

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1other than physics do u take entrepuener class

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1its like a business class

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2no!! never!!! why??

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1haha i kinda needed help

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1ok lol but if u dont knw it u dont have to help k

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1what is gross profit? A)the money left over after the cost of making a product or providing a service B) the cost of labor to produce a product C) the difference between a product's price and the revenue of the company D) a negative net profit, in which company experiences a loss

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2(finance) the net sales minus the cost of goods and services sold.

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1i gave u a medal right

tictac4456
 3 years ago
Best ResponseYou've already chosen the best response.1cool so did u graduate? or u still in high skool
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