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mayankdevnani
Group Title
A ball is dropped on to the floor from a height of 10 m. It reboundes to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, what is the average acceleration during contact?
a) \[1400 m/s^2\]
b) \[2100 m/s^2\]
c) \[700 m/s^2\]
d) \[2800 m/s^2\]
 one year ago
 one year ago
mayankdevnani Group Title
A ball is dropped on to the floor from a height of 10 m. It reboundes to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, what is the average acceleration during contact? a) \[1400 m/s^2\] b) \[2100 m/s^2\] c) \[700 m/s^2\] d) \[2800 m/s^2\]
 one year ago
 one year ago

This Question is Closed

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
@amistre64 @hba @asnaseer @AccessDenied @jhonyy9 @jazy @ganeshie8
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
The acceleration of a body is defined as the change of its velocity during an interval of time divided by the interval of time. Expressed algebraically, a = (Vo  Vf)/t where a = the acceleration, Vo = the initial velocity, Vf = the final velocity and t = the interval of time.
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
From the basic a = (Vo  Vf) we derive the first as ......................................t ..............................Vf = Vo + at (the acceleration is assumed constant)
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
The second defines the relationship between the distance traveled by a body exposed to a constant acceleration. The distance traveled over an interval of time derives from the product of the average velocity during the time interval and the time interval. The average velocity is (Vo + Vf)/2 and the time interval "t" which yields d = (Vo + Vf)t/2. Substituting the Vf derived above, d = [Vo + (Vo + at)]t/2 resulting in ...............................d = Vo(t) + a(t^2) (quite often, s is used in place of d) ......................................................2
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
The third combines the first two by eliminating the time interval "t". Therefore, a(d) = (Vo  Vf)(Vo + Vf)t = (1/2)(Vf  Vo)(Vf + Vo) resulting in .....................................t.............2 ..............................Vf^2 = Vo^2 + 2ad
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
thnx.... @tictac4456
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
no problem do u go to connexus
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
is it right?? While falling down, initial velocity = 0, final velocity = v, acceleration due to gravity = 9.8 m/s 2 , height = 10 m The velocity of the ball with which it hits the ground can be found using, v 2 = u 2 + 2as => v 2 = 0 + 2×9.8×10 => v = 14 m/s (downward) While it moves up, initial velocity = u, final velocity = 0, acceleration due to gravity = 9.8 m/s2 [this time the velocity and acceleration are oppositely directed so we have the negative sign] , height = 2.5 m The velocity of the ball with which it leaves the ground can be found using, v 2 = u 2 + 2as => 0 = u 2  2×9.8×2.5 => u = 7 m/s (upward) So, Change in velocity = 7 m/s (upward) – 14 m/s (downward) => Δv = 7 m/s + 14 m/s [both in upward direction] => Δv = 21 m/s So, acceleration is, a = Δv/Δt = 21/0.01 = 2100 m/s 2
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
@tictac4456
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
thats correct
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
thnx..
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
@satellite73 help me:)
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
@amistre64
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
hey ur work is correct but the answer is wrong
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
the answer is A
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
howz that??
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
oh im srry never mind i didnt see the seconds ur answer is correct
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
im 100% sure its right
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
ohkkk!!
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
I agree  your work and answer is correct
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
thnx...
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
do ya take entrepuener class
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
what do you mean??
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
other than physics do u take entrepuener class
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
its like a business class
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
no!! never!!! why??
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
haha i kinda needed help
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
but never mind
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
plz you can!!!
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
ok lol but if u dont knw it u dont have to help k
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
what is gross profit? A)the money left over after the cost of making a product or providing a service B) the cost of labor to produce a product C) the difference between a product's price and the revenue of the company D) a negative net profit, in which company experiences a loss
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
(finance) the net sales minus the cost of goods and services sold.
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
thnkz lol
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
i gave u a medal right
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
right!!!
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
cool so did u graduate? or u still in high skool
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
high school!!!
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
what grade
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
9 class
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
ok @tictac4456
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
me2 lol
 one year ago

tictac4456 Group TitleBest ResponseYou've already chosen the best response.1
what skool?
 one year ago
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