mayankdevnani
  • mayankdevnani
A ball is dropped on to the floor from a height of 10 m. It reboundes to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, what is the average acceleration during contact? a) \[1400 m/s^2\] b) \[2100 m/s^2\] c) \[700 m/s^2\] d) \[2800 m/s^2\]
Physics
jamiebookeater
  • jamiebookeater
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mayankdevnani
  • mayankdevnani
@amistre64 @hba @asnaseer @AccessDenied @jhonyy9 @jazy @ganeshie8
anonymous
  • anonymous
The acceleration of a body is defined as the change of its velocity during an interval of time divided by the interval of time. Expressed algebraically, a = (Vo - Vf)/t where a = the acceleration, Vo = the initial velocity, Vf = the final velocity and t = the interval of time.
anonymous
  • anonymous
From the basic a = (Vo - Vf) we derive the first as ......................................t ..............................Vf = Vo + at (the acceleration is assumed constant)

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anonymous
  • anonymous
The second defines the relationship between the distance traveled by a body exposed to a constant acceleration. The distance traveled over an interval of time derives from the product of the average velocity during the time interval and the time interval. The average velocity is (Vo + Vf)/2 and the time interval "t" which yields d = (Vo + Vf)t/2. Substituting the Vf derived above, d = [Vo + (Vo + at)]t/2 resulting in ...............................d = Vo(t) + a(t^2) (quite often, s is used in place of d) ......................................................2
anonymous
  • anonymous
The third combines the first two by eliminating the time interval "t". Therefore, a(d) = (Vo - Vf)(Vo + Vf)t = (1/2)(Vf - Vo)(Vf + Vo) resulting in .....................................t.............2 ..............................Vf^2 = Vo^2 + 2ad
mayankdevnani
  • mayankdevnani
thnx.... @tictac4456
anonymous
  • anonymous
no problem do u go to connexus
mayankdevnani
  • mayankdevnani
is it right?? While falling down, initial velocity = 0, final velocity = v, acceleration due to gravity = 9.8 m/s 2 , height = 10 m The velocity of the ball with which it hits the ground can be found using, v 2 = u 2 + 2as => v 2 = 0 + 2×9.8×10 => v = 14 m/s (downward) While it moves up, initial velocity = u, final velocity = 0, acceleration due to gravity = -9.8 m/s2 [this time the velocity and acceleration are oppositely directed so we have the negative sign] , height = 2.5 m The velocity of the ball with which it leaves the ground can be found using, v 2 = u 2 + 2as => 0 = u 2 - 2×9.8×2.5 => u = 7 m/s (upward) So, Change in velocity = 7 m/s (upward) – 14 m/s (downward) => Δv = 7 m/s + 14 m/s [both in upward direction] => Δv = 21 m/s So, acceleration is, a = Δv/Δt = 21/0.01 = 2100 m/s 2
anonymous
  • anonymous
yup
mayankdevnani
  • mayankdevnani
@tictac4456
anonymous
  • anonymous
thats correct
mayankdevnani
  • mayankdevnani
thnx..
mayankdevnani
  • mayankdevnani
@satellite73 help me:)
mayankdevnani
  • mayankdevnani
@amistre64
anonymous
  • anonymous
hey ur work is correct but the answer is wrong
anonymous
  • anonymous
the answer is A
mayankdevnani
  • mayankdevnani
howz that??
anonymous
  • anonymous
oh im srry never mind i didnt see the seconds ur answer is correct
anonymous
  • anonymous
im 100% sure its right
mayankdevnani
  • mayankdevnani
ohkkk!!
asnaseer
  • asnaseer
I agree - your work and answer is correct
mayankdevnani
  • mayankdevnani
thnx...
asnaseer
  • asnaseer
yw :)
anonymous
  • anonymous
do ya take entrepuener class
mayankdevnani
  • mayankdevnani
what do you mean??
anonymous
  • anonymous
other than physics do u take entrepuener class
anonymous
  • anonymous
its like a business class
mayankdevnani
  • mayankdevnani
no!! never!!! why??
anonymous
  • anonymous
haha i kinda needed help
anonymous
  • anonymous
but never mind
mayankdevnani
  • mayankdevnani
plz you can!!!
anonymous
  • anonymous
ok lol but if u dont knw it u dont have to help k
mayankdevnani
  • mayankdevnani
k
anonymous
  • anonymous
what is gross profit? A)the money left over after the cost of making a product or providing a service B) the cost of labor to produce a product C) the difference between a product's price and the revenue of the company D) a negative net profit, in which company experiences a loss
mayankdevnani
  • mayankdevnani
(finance) the net sales minus the cost of goods and services sold.
anonymous
  • anonymous
thnkz lol
anonymous
  • anonymous
i gave u a medal right
mayankdevnani
  • mayankdevnani
right!!!
anonymous
  • anonymous
cool so did u graduate? or u still in high skool
mayankdevnani
  • mayankdevnani
high school!!!
anonymous
  • anonymous
what grade
mayankdevnani
  • mayankdevnani
9 class
mayankdevnani
  • mayankdevnani
ok @tictac4456
anonymous
  • anonymous
me2 lol
anonymous
  • anonymous
what skool?

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