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mayankdevnani
 3 years ago
A ball is dropped on to the floor from a height of 10 m. It reboundes to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, what is the average acceleration during contact?
a) \[1400 m/s^2\]
b) \[2100 m/s^2\]
c) \[700 m/s^2\]
d) \[2800 m/s^2\]
mayankdevnani
 3 years ago
A ball is dropped on to the floor from a height of 10 m. It reboundes to a height of 2.5 m. If the ball is in contact with the floor for 0.01 seconds, what is the average acceleration during contact? a) \[1400 m/s^2\] b) \[2100 m/s^2\] c) \[700 m/s^2\] d) \[2800 m/s^2\]

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mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2@amistre64 @hba @asnaseer @AccessDenied @jhonyy9 @jazy @ganeshie8

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The acceleration of a body is defined as the change of its velocity during an interval of time divided by the interval of time. Expressed algebraically, a = (Vo  Vf)/t where a = the acceleration, Vo = the initial velocity, Vf = the final velocity and t = the interval of time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0From the basic a = (Vo  Vf) we derive the first as ......................................t ..............................Vf = Vo + at (the acceleration is assumed constant)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The second defines the relationship between the distance traveled by a body exposed to a constant acceleration. The distance traveled over an interval of time derives from the product of the average velocity during the time interval and the time interval. The average velocity is (Vo + Vf)/2 and the time interval "t" which yields d = (Vo + Vf)t/2. Substituting the Vf derived above, d = [Vo + (Vo + at)]t/2 resulting in ...............................d = Vo(t) + a(t^2) (quite often, s is used in place of d) ......................................................2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The third combines the first two by eliminating the time interval "t". Therefore, a(d) = (Vo  Vf)(Vo + Vf)t = (1/2)(Vf  Vo)(Vf + Vo) resulting in .....................................t.............2 ..............................Vf^2 = Vo^2 + 2ad

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2thnx.... @tictac4456

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no problem do u go to connexus

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2is it right?? While falling down, initial velocity = 0, final velocity = v, acceleration due to gravity = 9.8 m/s 2 , height = 10 m The velocity of the ball with which it hits the ground can be found using, v 2 = u 2 + 2as => v 2 = 0 + 2×9.8×10 => v = 14 m/s (downward) While it moves up, initial velocity = u, final velocity = 0, acceleration due to gravity = 9.8 m/s2 [this time the velocity and acceleration are oppositely directed so we have the negative sign] , height = 2.5 m The velocity of the ball with which it leaves the ground can be found using, v 2 = u 2 + 2as => 0 = u 2  2×9.8×2.5 => u = 7 m/s (upward) So, Change in velocity = 7 m/s (upward) – 14 m/s (downward) => Δv = 7 m/s + 14 m/s [both in upward direction] => Δv = 21 m/s So, acceleration is, a = Δv/Δt = 21/0.01 = 2100 m/s 2

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2@satellite73 help me:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hey ur work is correct but the answer is wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh im srry never mind i didnt see the seconds ur answer is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im 100% sure its right

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0I agree  your work and answer is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do ya take entrepuener class

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2what do you mean??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0other than physics do u take entrepuener class

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its like a business class

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2no!! never!!! why??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha i kinda needed help

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok lol but if u dont knw it u dont have to help k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is gross profit? A)the money left over after the cost of making a product or providing a service B) the cost of labor to produce a product C) the difference between a product's price and the revenue of the company D) a negative net profit, in which company experiences a loss

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.2(finance) the net sales minus the cost of goods and services sold.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i gave u a medal right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cool so did u graduate? or u still in high skool
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