## anonymous 3 years ago A 26.3 kg block (m1) is on a horizontal surface, connected to a 5.70 kg block (m2) by a massless string as shown in the figure below. The frictionless pulley has a radius R = 0.057 m and a moment of inertia I=0.090 kgm2. A force F = 192.9 N acts on m1 at an angle theta = 30.3°. There is no friction between m1 and the surface. What is the upward acceleration of m2?

1. anonymous

2. Qasim_Ahmed

look buddy i dont know the absolute solution for i dont recall the equation but i'll tell you what to do .. first you should analyse F to calculate the force component that acts on the system.. in this case this component equals $F * \cos \theta$ then you can calculate the m1's acceleration by newtons 2nd low $F = m_{1} a$ now comes my erased part of my memory ! you can write down the equation of inertia and put in your variables to find the up going acceleration i know i didn't made lot of help .. so please forgive me .. i have an important exam tomorrow in Plasma Physics and i am so distracted .. Good Luck

3. anonymous

Thanks Ahmed! Let me try this way and see. Also, good luck on your exam :)

4. anonymous

this may help