Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Solve. 3/2 x – 4 = 16 show your work please.

Geometry
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

Add 4 to both sides
3/2x = 20
Oh so you do the same, ok. then what?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

multiply by 2/3 on both sides
Get rid of the fraction by multiplying the denominator by 2 and 20 by 2
Then divide by 3
just multiply both sides by 2/3 because 2/3*3/2 is one, it will be cancelled and you will just have x on one side
I'm so confused. so multiply that and get 1 which is cancelled and then what?
3/2x = 20
Multiply 3/2 times 2 and 20 times 2
3x = 40
@FaithIsASiren_OhKellin? do you understand that?
When I multiplied the fraction by 2 it canceled out the denominator.
|dw:1353533796125:dw|
x=40/3 is answer
yeah, sorry. I get it now thanks.

Not the answer you are looking for?

Search for more explanations.

Ask your own question