Jose is paying for an 11$meal using bills in his wallet. He has four 1$ bills, two 5$ bills, and two 10 $bills. If he selects two bills at random, one at a time from his wallet, what is the probability that he will choose a 10$ bill and a 1$ bill to pay for the meal? Show your work.

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@tcarroll010
Please help:)

The probability is equal to \[=\frac{ 4 }{ 8 }\frac{ 2 }{ 7 }=\frac{ 1 }{ 7 }=0.142857\]

14.28%

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