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iAmCool

What percentage of the students surveyed babysat for at most eleven hours last weekend? Show your work. *Pic To Come*

  • one year ago
  • one year ago

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  1. iAmCool
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    |dw:1353543822540:dw|

    • one year ago
  2. jim_thompson5910
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    add up the heights of the first 3 bars to get your answer

    • one year ago
  3. iAmCool
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    Well, 5+10+25=40 .. then what?

    • one year ago
  4. iAmCool
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    40 is my answer?

    • one year ago
  5. jim_thompson5910
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    so there are 40 students who babysat for at most eleven hours there are 5+10+25+35 = 75 students total

    • one year ago
  6. iAmCool
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    So now I divide 40 by 75?

    • one year ago
  7. jim_thompson5910
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    so the percentage who babysat for at most eleven hours is (40/70)*100 = 57.1428% roughly

    • one year ago
  8. iAmCool
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    So 57% if rounded?

    • one year ago
  9. jim_thompson5910
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    yep

    • one year ago
  10. iAmCool
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    But why did you put 70 instead of 75.. :I

    • one year ago
  11. jim_thompson5910
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    oh my bad...i saw the 0 on 40 and thought it was 70, let me fix (40/75)*100 = 53.333%

    • one year ago
  12. jim_thompson5910
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    fixed

    • one year ago
  13. graydarl
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    75.........100% 40...........x% sox%=(40*100)/75 or (40/75)*100=53.33%

    • one year ago
  14. iAmCool
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    Thanks you;) And thank you graydarl too:)

    • one year ago
  15. graydarl
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    np :D

    • one year ago
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