anonymous
  • anonymous
What percentage of the students surveyed babysat for at most eleven hours last weekend? Show your work. *Pic To Come*
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1353543822540:dw|
jim_thompson5910
  • jim_thompson5910
add up the heights of the first 3 bars to get your answer
anonymous
  • anonymous
Well, 5+10+25=40 .. then what?

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anonymous
  • anonymous
40 is my answer?
jim_thompson5910
  • jim_thompson5910
so there are 40 students who babysat for at most eleven hours there are 5+10+25+35 = 75 students total
anonymous
  • anonymous
So now I divide 40 by 75?
jim_thompson5910
  • jim_thompson5910
so the percentage who babysat for at most eleven hours is (40/70)*100 = 57.1428% roughly
anonymous
  • anonymous
So 57% if rounded?
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
But why did you put 70 instead of 75.. :I
jim_thompson5910
  • jim_thompson5910
oh my bad...i saw the 0 on 40 and thought it was 70, let me fix (40/75)*100 = 53.333%
jim_thompson5910
  • jim_thompson5910
fixed
anonymous
  • anonymous
75.........100% 40...........x% sox%=(40*100)/75 or (40/75)*100=53.33%
anonymous
  • anonymous
Thanks you;) And thank you graydarl too:)
anonymous
  • anonymous
np :D

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