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Haleyyy Group Title

Which of the following is not a step used when graphing the equation x + 3y = 3 using the x- and y- intercepts method? (one sec while i graph)

  • 2 years ago
  • 2 years ago

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  1. Haleyyy Group Title
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    |dw:1353548335337:dw|

    • 2 years ago
  2. ByteMe Group Title
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    where are the steps?

    • 2 years ago
  3. freewilly922 Group Title
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    and I think you graphed it wrong. Shouldn't y intercept (when x=0) be 1?

    • 2 years ago
  4. Haleyyy Group Title
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    y = -5x + 5 y= -1/5x+5 y= 1/5x+5 y = 5x + 5

    • 2 years ago
  5. ByteMe Group Title
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    is that a different problem?

    • 2 years ago
  6. Haleyyy Group Title
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    Nope!

    • 2 years ago
  7. freewilly922 Group Title
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    |dw:1353548861029:dw| probably should look more like this

    • 2 years ago
  8. Haleyyy Group Title
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    It doesnt. It looks like how i graphed it.

    • 2 years ago
  9. ByteMe Group Title
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    what do those choices have to do with the original equation: "x + 3y = 3" ???

    • 2 years ago
  10. Haleyyy Group Title
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    I don't know, that's why i'm here lol

    • 2 years ago
  11. ByteMe Group Title
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    i don't think anyone can answer that either.... :)

    • 2 years ago
  12. freewilly922 Group Title
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    What you graphed is not x + 3y = 3 are you asking which equation is your graph?

    • 2 years ago
  13. Haleyyy Group Title
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    http://learn.flvs.net/webdav/assessment_images/educator_algebra1_v10/04_04_06.gif

    • 2 years ago
  14. Haleyyy Group Title
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    thats the graph

    • 2 years ago
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