The Survey of Study Habits and Attitudes (SSHA) is a psychological test that measures the motivation, attitudes, and study habits of college students. Scores range from 0 to 200 and follow (approximately) a Normal distribution, with mean of 115 and standard deviation 25. A researcher suspects that incoming freshmen have a mean μ, which is different from 115, because they are often excited yet anxious about entering college. To verify her suspicion, she tests the hypotheses
H0: μ = 115
Ha: μ 115.
The researcher gives the SSHA to 100 incoming freshmen and observes a mean score of 119. Assume that the scores of all incoming freshmen are approximately Normal with the same standard deviation as the scores of all college students.
Reference: Ref 13-5
If the researcher deems the data to be statistically significant, which of the following is true with respect to a conclusion reached?
A. The researcher has strong enough evidence to conclude that the average freshmen SSHA score differs from that of the average SSHA score for all college students.
B. The researcher does not have strong enough evidence to conclude that the average freshmen SSHA score differs from that of the average SSHA score for all college students.
C. The researcher has proven that the mean SSHA score for freshmen is, in fact, 115.
D. The researcher has proven that the mean SSHA score for freshmen is not 115.
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wait this is the Q we did 2 days ago LOL.
statistically significant means that p value < alpha -----> reject H0
Well it seems that A is the most correct answer, but D could be correct also.
sorry was chatting business with Dad.
there's a big difference between A and D though
some similarities... Because the score isn't 115, but the average of freshman is different from the overall.
A seems more logical as an answer tho :P
the big difference is that A says you can conclude it's not H0, D says you've proven it's not H0
technically, rejecting H0 does NOT mean you've fully proven it's not H0 since you could have made a type I error if this happens
so it's D? weak.
no i didn't say it was D
I'm saying D is not possible because you can't fully prove/disprove it since a type I error might occur