The free body diagram of the problem has 3 forces: 1) The Normal perpendicular to inclined plane. n=m*g=1.2*10=12 N 2) The friction parallel to inclined plane f=2.0 N 3) The weight that has two components, one perpendicular and other parallel (n*sin(30)) The Newton equation parallel to inclined plane is: $-f + m \times g \sin (30) = m \times a$ $a=acceleration=-f \div m + g \times \sin (30)= -2 \div 1.2 + 5 = 3.33 meters/\sec^{2}$