Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Josh1012 Group Title

4. A 1.2 kg block of mass is placed on an inclined plane that has a slope of 30° with respect to the horizontal, and the block of mass is released. A friction force Fk = 2.0 N acts on the block as it slides down the incline. Find the acceleration of the block down the incline

  • one year ago
  • one year ago

  • This Question is Closed
  1. galanh Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The free body diagram of the problem has 3 forces: 1) The Normal perpendicular to inclined plane. n=m*g=1.2*10=12 N 2) The friction parallel to inclined plane f=2.0 N 3) The weight that has two components, one perpendicular and other parallel (n*sin(30)) The Newton equation parallel to inclined plane is: \[-f + m \times g \sin (30) = m \times a\] \[a=acceleration=-f \div m + g \times \sin (30)= -2 \div 1.2 + 5 = 3.33 meters/\sec^{2}\]

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.