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anonymous
 4 years ago
cot[cos^−1(−1/2) + cos^−1(1/2) + tan^−1(1/3)]
anonymous
 4 years ago
cot[cos^−1(−1/2) + cos^−1(1/2) + tan^−1(1/3)]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\cos^{1}(\frac{1}{2})=120\] \[\cos^{1}(\frac{1}{2})=60\] \[\tan^{1}(\frac{1}{3})\] is a mystery to me but so far we have \[\cos(180+\tan^{1}(\frac{1}{3}))\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now \(\cos(180+x)=\cos(x)\) so your final job is to find \[\cos(\tan^{1}(\frac{1}{3}))\] which is identical to saying "if the tangent is 1/3, what is the cosine? you can do that by drawing a triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353554940402:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there is a picture of an angle whose tangent is \(\frac{1}{3}\) by pythagoras the hypotenuse is \(\sqrt{10}\) so the cosine of that angle is \[\frac{3}{\sqrt{10}}\] and so your answer is \[\frac{3}{\sqrt{10}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That makes so much sense, thank you for explaining it to me step by step! :)
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