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raerae01

  • 2 years ago

Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).

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  1. MathLegend
    • 2 years ago
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    First put the equation in the form of y=mx+b

  2. MathLegend
    • 2 years ago
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    -3y=-2x+12 -- ------- -3 -3 y = 2/3x - 4

  3. MathLegend
    • 2 years ago
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    Remember Perpendicular ... is reciprocal that is negative

  4. MathLegend
    • 2 years ago
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    y-6=-3/2(x-2) y-6=-3/2x+3 +6 +6 --------------- y = -3/2x + 9

  5. MathLegend
    • 2 years ago
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    @raerae01

  6. raerae01
    • 2 years ago
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    Thank you! So makes sense now! (:

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