Here's the question you clicked on:
raerae01
Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).
First put the equation in the form of y=mx+b
-3y=-2x+12 -- ------- -3 -3 y = 2/3x - 4
Remember Perpendicular ... is reciprocal that is negative
y-6=-3/2(x-2) y-6=-3/2x+3 +6 +6 --------------- y = -3/2x + 9
Thank you! So makes sense now! (: