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RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{dy}{dx} = \frac{x}{y^2\sqrt{1+x}}\]\[y^2dy = \frac{x}{\sqrt{1+x}}dx\]\[\frac{1}{3}y^3= \int \frac{u1}{u}du = \frac{2}{3} u^{\frac{3}{2}} 2u^{\frac{1}{2}}+C\]\[y = 2(1+x)^{\frac{3}{2}}6(1+x)^{\frac{1}{2}}+C)^{\frac{1}{3}}\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=integral+x%2Fsqrt%281%2Bx%29
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Did I do something wrong again?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
i couldn't understand clearly what u did, but it can be simplified to 2/3*(x2)*sqrt(x+1)
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Which part you didn't understand?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
then denominator is sqrt u
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
OMG!I typed something wrong!! \[\frac{1}{3}y^3= \int \frac{u1}{\sqrt u}du = \frac{2}{3} u^{\frac{3}{2}} 2u^{\frac{1}{2}}+C\]
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
No wonder why you couldn't understand.. That was my mistake :( Is that clear now?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
yeah...u can simplify your final answer by factoring out sqrt(x+1)
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
That's how the answer in my book looks like :S But thanks!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
ohh.. then no need. you were correct all along. welcome ^_^
 one year ago
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