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RolyPolyBest ResponseYou've already chosen the best response.1
\[(x+xy^2)dx + e^{x^2}ydy=0\]\[x(1+y^2)dx = e^{x^2}ydy\]\[\frac{x}{e^{x^2}}dx=\frac{y}{1+y^2}dy\]\[\frac{1}{2}e^{x^2}d(x^2)=\frac{1}{2(1+y^2)}d(y^2)\]\[\frac{1}{2}e^{x^2}+C=\frac{1}{2}\ln 1+y^2\]\[e^{x^2}+C=\ln 1+y^2\]Does it look fine?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
it looks correct to me.
 one year ago

cnkndBest ResponseYou've already chosen the best response.0
i dont see anything wrong here
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.1
Oh!! Thanks!! Should I further simplify it and make y as the subject or just leave it here?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
no, point.... that will just complicate the equation. exponential of exponential.....
 one year ago
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