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cnknd Group TitleBest ResponseYou've already chosen the best response.1
this is easily separable...
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
\[y' = x^3(1y)\]\[\frac{dy}{1y} = x^3 dx\]\[\ln 1y = \frac{1}{4}x^4+C\]So far so good?
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
lol I know, the whole chapter I'm doing now is separable.
 one year ago

cnknd Group TitleBest ResponseYou've already chosen the best response.1
ugh... check ur right hand side
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Right hand side? \[x^3 dx\]?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think its fine here u can isolate y easily.
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
If it's fine, then I continue.. y(0) = 3 \[\ln 13 = \frac{1}{4}(0)^4+C\]\[\ln 2 = C\] So far so good?
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Hmm.. ln2
 one year ago

cnknd Group TitleBest ResponseYou've already chosen the best response.1
ok x^2 does not integrate to 1/4*x^4
 one year ago

cnknd Group TitleBest ResponseYou've already chosen the best response.1
but C would still be ln2
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
It's x^3!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
continue....
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
So, \[\ln 1y = \frac{1}{4}(x)^4\ln 2\]\[\ln2\ln 1y = \frac{1}{4}(x)^4\]\[\ln\frac{2}{1y} = \frac{1}{4}(x)^4\]\[\frac{2}{1y} = e^{\frac{x^4}{4}}\]\[2= ({1y} )e^{\frac{x^4}{4}}\]\[y = \frac{e^{\frac{x^4}{4}}2}{\frace^{\frac{x^4}{4}}}{
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Sorry, please ignore the last line. OS just freezed my page.
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
But that doesn't look good at al..
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
better to do this \( \ln2+\ln 1y = \frac{1}{4}(x)^4\)
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
\[\ln2+\ln 1y = \frac{1}{4}x^4\]\[\frac{1y}{2}=e^{\frac{x^4}{4}}\]\[1y=2e^{\frac{x^4}{4}}\]\[y=12e^{\frac{x^4}{4}}\]
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Oh!! \[e^{\frac{x^4}{4}}\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
everything else is correct
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
Got it :)
 one year ago

cnknd Group TitleBest ResponseYou've already chosen the best response.1
\[\ln \left 1y \right = \frac{ 1 }{ 3 }x ^{3} + \ln2\] \[\left 1y \right = 2e^{\frac{ x ^{3} }{ 3 }}\] then you have to solve the absolute value part which gives u a piecewise function (this is a pain in the retrice
 one year ago

cnknd Group TitleBest ResponseYou've already chosen the best response.1
lol i like how they censor inappropriate words
 one year ago
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