1. geoffb

I would assign variables for the number of rooms for each cruise ship, then change the paragraph into equations.

2. MauriceLong

3. noseboy908

You should assign variables to the ships, not the rooms, since there is only one type of room.

4. MauriceLong

I am confuse with variables can you help me

5. noseboy908

yeah, in this situation, you have to assign the variables x, y, & z to each (respectably). So, how would you start?

6. MauriceLong

i have no clue at all.

7. MauriceLong

ok

8. noseboy908

ok, to start out, make x rep. the "Pacific Paradise", y the "Carribean Paradise", & z rep. the "Medditerranean Paradise". You need 3 equations to start, so start simple. we know that all the ships have a total of 881 "Deluxe Rooms", so what do you think could be our first equation?

9. MauriceLong

x+y+z

10. noseboy908

=?

11. MauriceLong

881

12. MauriceLong

ok

13. noseboy908

could you do me a favor and double-check your numbers in the how the problem is written?

14. MauriceLong

15. noseboy908

yes, but you are certain that the numbers are copied exactly as written in your textbook or workbook?

16. MauriceLong

Yes.

17. noseboy908

See, I keep coming up with the problem that I never get a whole, non-decimal number whenever I try to solve it. Allow me to explain my process.

18. MauriceLong

ok

19. noseboy908

|dw:1353566231443:dw|

20. MauriceLong

yes

21. noseboy908

Then I used substitution: z-29=4(y+28) Because it's stated in eqn. 1 that x= y+28. distribute: z-29=4y+112 add: z=4y+141. Next, I put (x=y+28), and (z=4y+141) into eqn. 3. To get: (y+28)+y+(4y+141)=881 Add the y's: 6y+169=881 subtract: 6y=712 divide: y=118.66. This is obviously incorrect, since you cannot have a decimal of a room. See any errors?

22. MauriceLong

no