anonymous
  • anonymous
Vertex form equation to standard form?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[y=5(x+3)^2-36\]
anonymous
  • anonymous
hba
  • hba
Sure...

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hba
  • hba
The vertex form is represented as \[ y= a(x-h)²+k\]
hba
  • hba
Lets see your question \[y=5(x+3)^2-36\] we know that (a+b)^2 = a^2+2ab+b^2 Now Please Use this formula and tell me what you get ?
anonymous
  • anonymous
sure, just a minute
hba
  • hba
Your standard form will look like, \[y = ax² + bx + c\]
anonymous
  • anonymous
I don't have a b?
hba
  • hba
Just show me what you got ?
shaik0124
  • shaik0124
if u solve u will get b
anonymous
  • anonymous
solving now
hba
  • hba
ok
shaik0124
  • shaik0124
solve
anonymous
  • anonymous
i got 0 = 10b... @_@ maybe i did something wrong
shaik0124
  • shaik0124
abba what emmah u did:P
hba
  • hba
Lets see your question y=5(x+3)^2−36 we know that (a+b)^2 = a^2+2ab+b^2 Now Please Use this formula and tell me what you get ? Just do this step and tell me.
hba
  • hba
Just apply the formula.....
anonymous
  • anonymous
I got 0 = 10b, or b=0.....
hba
  • hba
No let me show you wait
anonymous
  • anonymous
okay
shaik0124
  • shaik0124
just use ur mind emmah hba wait she will try
hba
  • hba
Just consider your question is (x+3)^2 according to formula (a+b)^2=a^2+2ab+b^2 here a =x and b=3 now just replace them
shaik0124
  • shaik0124
can i say answer hba
hba
  • hba
noooo
shaik0124
  • shaik0124
atleast she gets clarity
anonymous
  • anonymous
don't say the answer, if i don't try i'll never get it lol
hba
  • hba
Just try what i told you to do.
anonymous
  • anonymous
okay
hba
  • hba
Because you are not good with basic algebra.
hba
  • hba
Maybe i can put down a tutorial later on for you.
shaik0124
  • shaik0124
sh is good but mind is diverted now
hba
  • hba
If you have time.
anonymous
  • anonymous
I am good with basic algebra... i just don't understand what you're saying. I can do standard form to vertex form perfectly, but this is a little bit harder for me
hba
  • hba
You don't know how to apply a formula ?
anonymous
  • anonymous
sigh... no, i applied the formula and it worked out. a = 5 and b = 3
hba
  • hba
Let me show you an example (x+4)^2=x^2+2(x)(4)+4^2 =x^2+8x+16
hba
  • hba
Now just apply (x+3)^2
hba
  • hba
@shaik0124 Yaar tum iss ko ye solve karne do phir is equation mai dalwa daina.
hba
  • hba
Samjhe ?
shaik0124
  • shaik0124
x^2+6x+9 u will get hba right
hba
  • hba
Direct answer mat daina warna ban krdunga @shaik0124
anonymous
  • anonymous
(x+3)^2 = 64
shaik0124
  • shaik0124
ok
shaik0124
  • shaik0124
YAAR BAN KAISE KARTHE HAIN
anonymous
  • anonymous
?_?
hba
  • hba
@Emmy82650 I got (x+4)^2=x^2+8x+167 and you got (x+3)^2=64 , Are you serious ?
shaik0124
  • shaik0124
HAHA
anonymous
  • anonymous
.... Well, i think we're done here.
hba
  • hba
@Emmy82650 If you can come here after 2 hours i am putting down a tutorial for you,understood.
anonymous
  • anonymous
no thank you
hba
  • hba
Maths is the easiest subject and you are failing badly to understand.
hba
  • hba
My tutorials are for all so even if you don't want it others will benefit.
anonymous
  • anonymous
i will find another way to learn it. I don't feel like dealing with rude people at the moment. and yes, i understand math. I am taking am algebra 2 gifted honors course
shaik0124
  • shaik0124
emmah can i help u
anonymous
  • anonymous
no thank you..
shaik0124
  • shaik0124
ok nice
shaik0124
  • shaik0124
|dw:1353593622282:dw|
anonymous
  • anonymous
is that a 62? a little hard to read
shaik0124
  • shaik0124
6x
anonymous
  • anonymous
so y= 5(x^2 +9+6x) - 36?
shaik0124
  • shaik0124
yes
shaik0124
  • shaik0124
now multiply with 5 in rhside and solve
anonymous
  • anonymous
in rhside?
shaik0124
  • shaik0124
right hand side
anonymous
  • anonymous
that doesn't make sense, that's not what the formula would come to in the end
anonymous
  • anonymous
emmy would you still like help
anonymous
  • anonymous
yes please, if you can give it
anonymous
  • anonymous
You have \[\left( x+3 \right)^{2}\] This means \[\left( x+3 \right)\left( x+3 \right)\] Do you know how to expand this?
shaik0124
  • shaik0124
skae give answer directly bcoz she doesn't
anonymous
  • anonymous
Im not asking you shaik
shaik0124
  • shaik0124
|dw:1353594458544:dw|
shaik0124
  • shaik0124
skae everything was explained to her see above comments
anonymous
  • anonymous
(x+3)^2?
shaik0124
  • shaik0124
dont make time pass here emmy b serious
anonymous
  • anonymous
(x+3)(x+3)?
anonymous
  • anonymous
@shaik0124 UGH i'm being serious! the equation didn't show up right on my computer,idk if it did for yours but it looks jumbled on mine! If you don't want to help you can just click on another question and leave me alone PLEASE.
anonymous
  • anonymous
yes (x+3)(x+3)
anonymous
  • anonymous
okay, where do i go from there?
anonymous
  • anonymous
Do you know how to expand something like 2(x+3)
anonymous
  • anonymous
2(x+3) = 2x + 6 (x+3)(x+3) is the same concept but now you have 2 terms instead of 2 You get 3 terms: x*x, x*3, 3*x, 3*3 (x+3)(x+3) = x^2 + 9 + 3x + 3x
anonymous
  • anonymous
okay i understand that somewhat
anonymous
  • anonymous
so for this problem it's 5(x+3)^2 (5x+15)^2? (5x+15)(5x+15) = 5x^2 + 225 + 75x + 75x? 5x^2 + 225 + 150x?
anonymous
  • anonymous
No you have to expand the (x+3)^2 first before multiplying by 5 (x+3)^2 = ?
anonymous
  • anonymous
ohhh sorry. so: (x+3)(x+3) = x^2 + 9 + 9x and then multiply by five
anonymous
  • anonymous
uhm 5x^2 + 45 + 45x
anonymous
  • anonymous
You get X^2, 9, 3x and 3x from the expansion What is 3x + 3x? x^2 + 9 + 3x + 3x = x^2 + 9 + 6x
anonymous
  • anonymous
crap i messed up again... 5x^2 + 30x + 45
anonymous
  • anonymous
yup thats right now minus 36 What is the final answer?
anonymous
  • anonymous
5x^2 + 30x + 9
anonymous
  • anonymous
good job
anonymous
  • anonymous
Thats of the form \[y= ax^{2} + bx + c\] where a=5, b=30 and c=9
anonymous
  • anonymous
thank you so much, i finally understand! :)
anonymous
  • anonymous
no problem :)

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