Vertex form equation to standard form?

- anonymous

Vertex form equation to standard form?

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- anonymous

\[y=5(x+3)^2-36\]

- anonymous

@hba ?

- hba

Sure...

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## More answers

- hba

The vertex form is represented as
\[ y= a(x-h)²+k\]

- hba

Lets see your question
\[y=5(x+3)^2-36\]
we know that (a+b)^2 = a^2+2ab+b^2
Now Please Use this formula and tell me what you get ?

- anonymous

sure, just a minute

- hba

Your standard form will look like,
\[y = ax² + bx + c\]

- anonymous

I don't have a b?

- hba

Just show me what you got ?

- shaik0124

if u solve u will get b

- anonymous

solving now

- hba

ok

- shaik0124

solve

- anonymous

i got 0 = 10b... @_@ maybe i did something wrong

- shaik0124

abba what emmah u did:P

- hba

Lets see your question
y=5(x+3)^2−36
we know that (a+b)^2 = a^2+2ab+b^2
Now Please Use this formula and tell me what you get ?
Just do this step and tell me.

- hba

Just apply the formula.....

- anonymous

I got 0 = 10b, or b=0.....

- hba

No let me show you wait

- anonymous

okay

- shaik0124

just use ur mind emmah hba wait she will try

- hba

Just consider your question is (x+3)^2
according to formula (a+b)^2=a^2+2ab+b^2
here a =x and b=3 now just replace them

- shaik0124

can i say answer hba

- hba

noooo

- shaik0124

atleast she gets clarity

- anonymous

don't say the answer, if i don't try i'll never get it lol

- hba

Just try what i told you to do.

- anonymous

okay

- hba

Because you are not good with basic algebra.

- hba

Maybe i can put down a tutorial later on for you.

- shaik0124

sh is good but mind is diverted now

- hba

If you have time.

- anonymous

I am good with basic algebra... i just don't understand what you're saying. I can do standard form to vertex form perfectly, but this is a little bit harder for me

- hba

You don't know how to apply a formula ?

- anonymous

sigh...
no, i applied the formula and it worked out. a = 5 and b = 3

- hba

Let me show you an example
(x+4)^2=x^2+2(x)(4)+4^2
=x^2+8x+16

- hba

Now just apply (x+3)^2

- hba

@shaik0124 Yaar tum iss ko ye solve karne do phir is equation mai dalwa daina.

- hba

Samjhe ?

- shaik0124

x^2+6x+9 u will get hba right

- hba

Direct answer mat daina warna ban krdunga @shaik0124

- anonymous

(x+3)^2 = 64

- shaik0124

ok

- shaik0124

YAAR BAN KAISE KARTHE HAIN

- anonymous

?_?

- hba

@Emmy82650 I got (x+4)^2=x^2+8x+167
and you got (x+3)^2=64 , Are you serious ?

- shaik0124

HAHA

- anonymous

.... Well, i think we're done here.

- hba

@Emmy82650 If you can come here after 2 hours i am putting down a tutorial for you,understood.

- anonymous

no thank you

- hba

Maths is the easiest subject and you are failing badly to understand.

- hba

My tutorials are for all so even if you don't want it others will benefit.

- anonymous

i will find another way to learn it. I don't feel like dealing with rude people at the moment. and yes, i understand math. I am taking am algebra 2 gifted honors course

- shaik0124

emmah can i help u

- anonymous

no thank you..

- shaik0124

ok nice

- shaik0124

|dw:1353593622282:dw|

- anonymous

is that a 62? a little hard to read

- shaik0124

6x

- anonymous

so y= 5(x^2 +9+6x) - 36?

- shaik0124

yes

- shaik0124

now multiply with 5 in rhside and solve

- anonymous

in rhside?

- shaik0124

right hand side

- anonymous

that doesn't make sense, that's not what the formula would come to in the end

- anonymous

emmy would you still like help

- anonymous

yes please, if you can give it

- anonymous

You have \[\left( x+3 \right)^{2}\]
This means
\[\left( x+3 \right)\left( x+3 \right)\]
Do you know how to expand this?

- shaik0124

skae give answer directly bcoz she doesn't

- anonymous

Im not asking you shaik

- shaik0124

|dw:1353594458544:dw|

- shaik0124

skae everything was explained to her see above comments

- anonymous

(x+3)^2?

- shaik0124

dont make time pass here emmy b serious

- anonymous

(x+3)(x+3)?

- anonymous

@shaik0124 UGH i'm being serious! the equation didn't show up right on my computer,idk if it did for yours but it looks jumbled on mine! If you don't want to help you can just click on another question and leave me alone PLEASE.

- anonymous

yes (x+3)(x+3)

- anonymous

okay, where do i go from there?

- anonymous

Do you know how to expand something like 2(x+3)

- anonymous

2(x+3) = 2x + 6
(x+3)(x+3) is the same concept but now you have 2 terms instead of 2
You get 3 terms: x*x, x*3, 3*x, 3*3
(x+3)(x+3) = x^2 + 9 + 3x + 3x

- anonymous

okay i understand that somewhat

- anonymous

so for this problem it's 5(x+3)^2
(5x+15)^2?
(5x+15)(5x+15) = 5x^2 + 225 + 75x + 75x?
5x^2 + 225 + 150x?

- anonymous

No you have to expand the (x+3)^2 first before multiplying by 5
(x+3)^2 = ?

- anonymous

ohhh sorry. so:
(x+3)(x+3) = x^2 + 9 + 9x and then multiply by five

- anonymous

uhm 5x^2 + 45 + 45x

- anonymous

You get X^2, 9, 3x and 3x from the expansion
What is 3x + 3x?
x^2 + 9 + 3x + 3x = x^2 + 9 + 6x

- anonymous

crap i messed up again...
5x^2 + 30x + 45

- anonymous

yup thats right
now minus 36
What is the final answer?

- anonymous

5x^2 + 30x + 9

- anonymous

good job

- anonymous

Thats of the form \[y= ax^{2} + bx + c\]
where a=5, b=30 and c=9

- anonymous

thank you so much, i finally understand! :)

- anonymous

no problem :)

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