## Emmy82650 3 years ago Vertex form equation to standard form?

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1. Emmy82650

$y=5(x+3)^2-36$

2. Emmy82650

@hba ?

3. hba

Sure...

4. hba

The vertex form is represented as $y= a(x-h)²+k$

5. hba

Lets see your question $y=5(x+3)^2-36$ we know that (a+b)^2 = a^2+2ab+b^2 Now Please Use this formula and tell me what you get ?

6. Emmy82650

sure, just a minute

7. hba

Your standard form will look like, $y = ax² + bx + c$

8. Emmy82650

I don't have a b?

9. hba

Just show me what you got ?

10. shaik0124

if u solve u will get b

11. Emmy82650

solving now

12. hba

ok

13. shaik0124

solve

14. Emmy82650

i got 0 = 10b... @_@ maybe i did something wrong

15. shaik0124

abba what emmah u did:P

16. hba

Lets see your question y=5(x+3)^2−36 we know that (a+b)^2 = a^2+2ab+b^2 Now Please Use this formula and tell me what you get ? Just do this step and tell me.

17. hba

Just apply the formula.....

18. Emmy82650

I got 0 = 10b, or b=0.....

19. hba

No let me show you wait

20. Emmy82650

okay

21. shaik0124

just use ur mind emmah hba wait she will try

22. hba

Just consider your question is (x+3)^2 according to formula (a+b)^2=a^2+2ab+b^2 here a =x and b=3 now just replace them

23. shaik0124

24. hba

noooo

25. shaik0124

atleast she gets clarity

26. Emmy82650

don't say the answer, if i don't try i'll never get it lol

27. hba

Just try what i told you to do.

28. Emmy82650

okay

29. hba

Because you are not good with basic algebra.

30. hba

Maybe i can put down a tutorial later on for you.

31. shaik0124

sh is good but mind is diverted now

32. hba

If you have time.

33. Emmy82650

I am good with basic algebra... i just don't understand what you're saying. I can do standard form to vertex form perfectly, but this is a little bit harder for me

34. hba

You don't know how to apply a formula ?

35. Emmy82650

sigh... no, i applied the formula and it worked out. a = 5 and b = 3

36. hba

Let me show you an example (x+4)^2=x^2+2(x)(4)+4^2 =x^2+8x+16

37. hba

Now just apply (x+3)^2

38. hba

@shaik0124 Yaar tum iss ko ye solve karne do phir is equation mai dalwa daina.

39. hba

Samjhe ?

40. shaik0124

x^2+6x+9 u will get hba right

41. hba

Direct answer mat daina warna ban krdunga @shaik0124

42. Emmy82650

(x+3)^2 = 64

43. shaik0124

ok

44. shaik0124

YAAR BAN KAISE KARTHE HAIN

45. Emmy82650

?_?

46. hba

@Emmy82650 I got (x+4)^2=x^2+8x+167 and you got (x+3)^2=64 , Are you serious ?

47. shaik0124

HAHA

48. Emmy82650

.... Well, i think we're done here.

49. hba

@Emmy82650 If you can come here after 2 hours i am putting down a tutorial for you,understood.

50. Emmy82650

no thank you

51. hba

Maths is the easiest subject and you are failing badly to understand.

52. hba

My tutorials are for all so even if you don't want it others will benefit.

53. Emmy82650

i will find another way to learn it. I don't feel like dealing with rude people at the moment. and yes, i understand math. I am taking am algebra 2 gifted honors course

54. shaik0124

emmah can i help u

55. Emmy82650

no thank you..

56. shaik0124

ok nice

57. shaik0124

|dw:1353593622282:dw|

58. Emmy82650

is that a 62? a little hard to read

59. shaik0124

6x

60. Emmy82650

so y= 5(x^2 +9+6x) - 36?

61. shaik0124

yes

62. shaik0124

now multiply with 5 in rhside and solve

63. Emmy82650

in rhside?

64. shaik0124

right hand side

65. Emmy82650

that doesn't make sense, that's not what the formula would come to in the end

66. Skaematik

emmy would you still like help

67. Emmy82650

yes please, if you can give it

68. Skaematik

You have $\left( x+3 \right)^{2}$ This means $\left( x+3 \right)\left( x+3 \right)$ Do you know how to expand this?

69. shaik0124

skae give answer directly bcoz she doesn't

70. Skaematik

71. shaik0124

|dw:1353594458544:dw|

72. shaik0124

skae everything was explained to her see above comments

73. Emmy82650

(x+3)^2?

74. shaik0124

dont make time pass here emmy b serious

75. Emmy82650

(x+3)(x+3)?

76. Emmy82650

@shaik0124 UGH i'm being serious! the equation didn't show up right on my computer,idk if it did for yours but it looks jumbled on mine! If you don't want to help you can just click on another question and leave me alone PLEASE.

77. Skaematik

yes (x+3)(x+3)

78. Emmy82650

okay, where do i go from there?

79. Skaematik

Do you know how to expand something like 2(x+3)

80. Skaematik

2(x+3) = 2x + 6 (x+3)(x+3) is the same concept but now you have 2 terms instead of 2 You get 3 terms: x*x, x*3, 3*x, 3*3 (x+3)(x+3) = x^2 + 9 + 3x + 3x

81. Emmy82650

okay i understand that somewhat

82. Emmy82650

so for this problem it's 5(x+3)^2 (5x+15)^2? (5x+15)(5x+15) = 5x^2 + 225 + 75x + 75x? 5x^2 + 225 + 150x?

83. Skaematik

No you have to expand the (x+3)^2 first before multiplying by 5 (x+3)^2 = ?

84. Emmy82650

ohhh sorry. so: (x+3)(x+3) = x^2 + 9 + 9x and then multiply by five

85. Emmy82650

uhm 5x^2 + 45 + 45x

86. Skaematik

You get X^2, 9, 3x and 3x from the expansion What is 3x + 3x? x^2 + 9 + 3x + 3x = x^2 + 9 + 6x

87. Emmy82650

crap i messed up again... 5x^2 + 30x + 45

88. Skaematik

yup thats right now minus 36 What is the final answer?

89. Emmy82650

5x^2 + 30x + 9

90. Skaematik

good job

91. Skaematik

Thats of the form $y= ax^{2} + bx + c$ where a=5, b=30 and c=9

92. Emmy82650

thank you so much, i finally understand! :)

93. Skaematik

no problem :)