Emmy82650
Vertex form equation to standard form?
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Emmy82650
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\[y=5(x+3)^2-36\]
Emmy82650
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@hba ?
hba
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Sure...
hba
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The vertex form is represented as
\[ y= a(x-h)²+k\]
hba
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Lets see your question
\[y=5(x+3)^2-36\]
we know that (a+b)^2 = a^2+2ab+b^2
Now Please Use this formula and tell me what you get ?
Emmy82650
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sure, just a minute
hba
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Your standard form will look like,
\[y = ax² + bx + c\]
Emmy82650
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I don't have a b?
hba
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Just show me what you got ?
shaik0124
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if u solve u will get b
Emmy82650
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solving now
hba
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ok
shaik0124
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solve
Emmy82650
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i got 0 = 10b... @_@ maybe i did something wrong
shaik0124
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abba what emmah u did:P
hba
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Lets see your question
y=5(x+3)^2−36
we know that (a+b)^2 = a^2+2ab+b^2
Now Please Use this formula and tell me what you get ?
Just do this step and tell me.
hba
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Just apply the formula.....
Emmy82650
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I got 0 = 10b, or b=0.....
hba
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No let me show you wait
Emmy82650
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okay
shaik0124
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just use ur mind emmah hba wait she will try
hba
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Just consider your question is (x+3)^2
according to formula (a+b)^2=a^2+2ab+b^2
here a =x and b=3 now just replace them
shaik0124
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can i say answer hba
hba
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noooo
shaik0124
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atleast she gets clarity
Emmy82650
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don't say the answer, if i don't try i'll never get it lol
hba
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Just try what i told you to do.
Emmy82650
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okay
hba
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Because you are not good with basic algebra.
hba
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Maybe i can put down a tutorial later on for you.
shaik0124
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sh is good but mind is diverted now
hba
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If you have time.
Emmy82650
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I am good with basic algebra... i just don't understand what you're saying. I can do standard form to vertex form perfectly, but this is a little bit harder for me
hba
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You don't know how to apply a formula ?
Emmy82650
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sigh...
no, i applied the formula and it worked out. a = 5 and b = 3
hba
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Let me show you an example
(x+4)^2=x^2+2(x)(4)+4^2
=x^2+8x+16
hba
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Now just apply (x+3)^2
hba
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@shaik0124 Yaar tum iss ko ye solve karne do phir is equation mai dalwa daina.
hba
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Samjhe ?
shaik0124
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x^2+6x+9 u will get hba right
hba
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Direct answer mat daina warna ban krdunga @shaik0124
Emmy82650
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(x+3)^2 = 64
shaik0124
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ok
shaik0124
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YAAR BAN KAISE KARTHE HAIN
Emmy82650
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?_?
hba
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@Emmy82650 I got (x+4)^2=x^2+8x+167
and you got (x+3)^2=64 , Are you serious ?
shaik0124
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HAHA
Emmy82650
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.... Well, i think we're done here.
hba
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@Emmy82650 If you can come here after 2 hours i am putting down a tutorial for you,understood.
Emmy82650
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no thank you
hba
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Maths is the easiest subject and you are failing badly to understand.
hba
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My tutorials are for all so even if you don't want it others will benefit.
Emmy82650
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i will find another way to learn it. I don't feel like dealing with rude people at the moment. and yes, i understand math. I am taking am algebra 2 gifted honors course
shaik0124
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emmah can i help u
Emmy82650
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no thank you..
shaik0124
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ok nice
shaik0124
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|dw:1353593622282:dw|
Emmy82650
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is that a 62? a little hard to read
shaik0124
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6x
Emmy82650
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so y= 5(x^2 +9+6x) - 36?
shaik0124
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yes
shaik0124
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now multiply with 5 in rhside and solve
Emmy82650
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in rhside?
shaik0124
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right hand side
Emmy82650
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that doesn't make sense, that's not what the formula would come to in the end
Skaematik
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emmy would you still like help
Emmy82650
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yes please, if you can give it
Skaematik
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You have \[\left( x+3 \right)^{2}\]
This means
\[\left( x+3 \right)\left( x+3 \right)\]
Do you know how to expand this?
shaik0124
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skae give answer directly bcoz she doesn't
Skaematik
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Im not asking you shaik
shaik0124
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|dw:1353594458544:dw|
shaik0124
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skae everything was explained to her see above comments
Emmy82650
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(x+3)^2?
shaik0124
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dont make time pass here emmy b serious
Emmy82650
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(x+3)(x+3)?
Emmy82650
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@shaik0124 UGH i'm being serious! the equation didn't show up right on my computer,idk if it did for yours but it looks jumbled on mine! If you don't want to help you can just click on another question and leave me alone PLEASE.
Skaematik
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yes (x+3)(x+3)
Emmy82650
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okay, where do i go from there?
Skaematik
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Do you know how to expand something like 2(x+3)
Skaematik
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2(x+3) = 2x + 6
(x+3)(x+3) is the same concept but now you have 2 terms instead of 2
You get 3 terms: x*x, x*3, 3*x, 3*3
(x+3)(x+3) = x^2 + 9 + 3x + 3x
Emmy82650
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okay i understand that somewhat
Emmy82650
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so for this problem it's 5(x+3)^2
(5x+15)^2?
(5x+15)(5x+15) = 5x^2 + 225 + 75x + 75x?
5x^2 + 225 + 150x?
Skaematik
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No you have to expand the (x+3)^2 first before multiplying by 5
(x+3)^2 = ?
Emmy82650
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ohhh sorry. so:
(x+3)(x+3) = x^2 + 9 + 9x and then multiply by five
Emmy82650
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uhm 5x^2 + 45 + 45x
Skaematik
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You get X^2, 9, 3x and 3x from the expansion
What is 3x + 3x?
x^2 + 9 + 3x + 3x = x^2 + 9 + 6x
Emmy82650
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crap i messed up again...
5x^2 + 30x + 45
Skaematik
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yup thats right
now minus 36
What is the final answer?
Emmy82650
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5x^2 + 30x + 9
Skaematik
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good job
Skaematik
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Thats of the form \[y= ax^{2} + bx + c\]
where a=5, b=30 and c=9
Emmy82650
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thank you so much, i finally understand! :)
Skaematik
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no problem :)