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Emmy82650

  • 2 years ago

Vertex form equation to standard form?

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  1. Emmy82650
    • 2 years ago
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    \[y=5(x+3)^2-36\]

  2. Emmy82650
    • 2 years ago
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    @hba ?

  3. hba
    • 2 years ago
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    Sure...

  4. hba
    • 2 years ago
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    The vertex form is represented as \[ y= a(x-h)²+k\]

  5. hba
    • 2 years ago
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    Lets see your question \[y=5(x+3)^2-36\] we know that (a+b)^2 = a^2+2ab+b^2 Now Please Use this formula and tell me what you get ?

  6. Emmy82650
    • 2 years ago
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    sure, just a minute

  7. hba
    • 2 years ago
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    Your standard form will look like, \[y = ax² + bx + c\]

  8. Emmy82650
    • 2 years ago
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    I don't have a b?

  9. hba
    • 2 years ago
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    Just show me what you got ?

  10. shaik0124
    • 2 years ago
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    if u solve u will get b

  11. Emmy82650
    • 2 years ago
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    solving now

  12. hba
    • 2 years ago
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    ok

  13. shaik0124
    • 2 years ago
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    solve

  14. Emmy82650
    • 2 years ago
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    i got 0 = 10b... @_@ maybe i did something wrong

  15. shaik0124
    • 2 years ago
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    abba what emmah u did:P

  16. hba
    • 2 years ago
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    Lets see your question y=5(x+3)^2−36 we know that (a+b)^2 = a^2+2ab+b^2 Now Please Use this formula and tell me what you get ? Just do this step and tell me.

  17. hba
    • 2 years ago
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    Just apply the formula.....

  18. Emmy82650
    • 2 years ago
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    I got 0 = 10b, or b=0.....

  19. hba
    • 2 years ago
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    No let me show you wait

  20. Emmy82650
    • 2 years ago
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    okay

  21. shaik0124
    • 2 years ago
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    just use ur mind emmah hba wait she will try

  22. hba
    • 2 years ago
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    Just consider your question is (x+3)^2 according to formula (a+b)^2=a^2+2ab+b^2 here a =x and b=3 now just replace them

  23. shaik0124
    • 2 years ago
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    can i say answer hba

  24. hba
    • 2 years ago
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    noooo

  25. shaik0124
    • 2 years ago
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    atleast she gets clarity

  26. Emmy82650
    • 2 years ago
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    don't say the answer, if i don't try i'll never get it lol

  27. hba
    • 2 years ago
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    Just try what i told you to do.

  28. Emmy82650
    • 2 years ago
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    okay

  29. hba
    • 2 years ago
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    Because you are not good with basic algebra.

  30. hba
    • 2 years ago
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    Maybe i can put down a tutorial later on for you.

  31. shaik0124
    • 2 years ago
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    sh is good but mind is diverted now

  32. hba
    • 2 years ago
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    If you have time.

  33. Emmy82650
    • 2 years ago
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    I am good with basic algebra... i just don't understand what you're saying. I can do standard form to vertex form perfectly, but this is a little bit harder for me

  34. hba
    • 2 years ago
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    You don't know how to apply a formula ?

  35. Emmy82650
    • 2 years ago
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    sigh... no, i applied the formula and it worked out. a = 5 and b = 3

  36. hba
    • 2 years ago
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    Let me show you an example (x+4)^2=x^2+2(x)(4)+4^2 =x^2+8x+16

  37. hba
    • 2 years ago
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    Now just apply (x+3)^2

  38. hba
    • 2 years ago
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    @shaik0124 Yaar tum iss ko ye solve karne do phir is equation mai dalwa daina.

  39. hba
    • 2 years ago
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    Samjhe ?

  40. shaik0124
    • 2 years ago
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    x^2+6x+9 u will get hba right

  41. hba
    • 2 years ago
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    Direct answer mat daina warna ban krdunga @shaik0124

  42. Emmy82650
    • 2 years ago
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    (x+3)^2 = 64

  43. shaik0124
    • 2 years ago
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    ok

  44. shaik0124
    • 2 years ago
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    YAAR BAN KAISE KARTHE HAIN

  45. Emmy82650
    • 2 years ago
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    ?_?

  46. hba
    • 2 years ago
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    @Emmy82650 I got (x+4)^2=x^2+8x+167 and you got (x+3)^2=64 , Are you serious ?

  47. shaik0124
    • 2 years ago
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    HAHA

  48. Emmy82650
    • 2 years ago
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    .... Well, i think we're done here.

  49. hba
    • 2 years ago
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    @Emmy82650 If you can come here after 2 hours i am putting down a tutorial for you,understood.

  50. Emmy82650
    • 2 years ago
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    no thank you

  51. hba
    • 2 years ago
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    Maths is the easiest subject and you are failing badly to understand.

  52. hba
    • 2 years ago
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    My tutorials are for all so even if you don't want it others will benefit.

  53. Emmy82650
    • 2 years ago
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    i will find another way to learn it. I don't feel like dealing with rude people at the moment. and yes, i understand math. I am taking am algebra 2 gifted honors course

  54. shaik0124
    • 2 years ago
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    emmah can i help u

  55. Emmy82650
    • 2 years ago
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    no thank you..

  56. shaik0124
    • 2 years ago
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    ok nice

  57. shaik0124
    • 2 years ago
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    |dw:1353593622282:dw|

  58. Emmy82650
    • 2 years ago
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    is that a 62? a little hard to read

  59. shaik0124
    • 2 years ago
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    6x

  60. Emmy82650
    • 2 years ago
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    so y= 5(x^2 +9+6x) - 36?

  61. shaik0124
    • 2 years ago
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    yes

  62. shaik0124
    • 2 years ago
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    now multiply with 5 in rhside and solve

  63. Emmy82650
    • 2 years ago
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    in rhside?

  64. shaik0124
    • 2 years ago
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    right hand side

  65. Emmy82650
    • 2 years ago
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    that doesn't make sense, that's not what the formula would come to in the end

  66. Skaematik
    • 2 years ago
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    emmy would you still like help

  67. Emmy82650
    • 2 years ago
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    yes please, if you can give it

  68. Skaematik
    • 2 years ago
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    You have \[\left( x+3 \right)^{2}\] This means \[\left( x+3 \right)\left( x+3 \right)\] Do you know how to expand this?

  69. shaik0124
    • 2 years ago
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    skae give answer directly bcoz she doesn't

  70. Skaematik
    • 2 years ago
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    Im not asking you shaik

  71. shaik0124
    • 2 years ago
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    |dw:1353594458544:dw|

  72. shaik0124
    • 2 years ago
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    skae everything was explained to her see above comments

  73. Emmy82650
    • 2 years ago
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    (x+3)^2?

  74. shaik0124
    • 2 years ago
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    dont make time pass here emmy b serious

  75. Emmy82650
    • 2 years ago
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    (x+3)(x+3)?

  76. Emmy82650
    • 2 years ago
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    @shaik0124 UGH i'm being serious! the equation didn't show up right on my computer,idk if it did for yours but it looks jumbled on mine! If you don't want to help you can just click on another question and leave me alone PLEASE.

  77. Skaematik
    • 2 years ago
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    yes (x+3)(x+3)

  78. Emmy82650
    • 2 years ago
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    okay, where do i go from there?

  79. Skaematik
    • 2 years ago
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    Do you know how to expand something like 2(x+3)

  80. Skaematik
    • 2 years ago
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    2(x+3) = 2x + 6 (x+3)(x+3) is the same concept but now you have 2 terms instead of 2 You get 3 terms: x*x, x*3, 3*x, 3*3 (x+3)(x+3) = x^2 + 9 + 3x + 3x

  81. Emmy82650
    • 2 years ago
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    okay i understand that somewhat

  82. Emmy82650
    • 2 years ago
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    so for this problem it's 5(x+3)^2 (5x+15)^2? (5x+15)(5x+15) = 5x^2 + 225 + 75x + 75x? 5x^2 + 225 + 150x?

  83. Skaematik
    • 2 years ago
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    No you have to expand the (x+3)^2 first before multiplying by 5 (x+3)^2 = ?

  84. Emmy82650
    • 2 years ago
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    ohhh sorry. so: (x+3)(x+3) = x^2 + 9 + 9x and then multiply by five

  85. Emmy82650
    • 2 years ago
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    uhm 5x^2 + 45 + 45x

  86. Skaematik
    • 2 years ago
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    You get X^2, 9, 3x and 3x from the expansion What is 3x + 3x? x^2 + 9 + 3x + 3x = x^2 + 9 + 6x

  87. Emmy82650
    • 2 years ago
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    crap i messed up again... 5x^2 + 30x + 45

  88. Skaematik
    • 2 years ago
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    yup thats right now minus 36 What is the final answer?

  89. Emmy82650
    • 2 years ago
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    5x^2 + 30x + 9

  90. Skaematik
    • 2 years ago
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    good job

  91. Skaematik
    • 2 years ago
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    Thats of the form \[y= ax^{2} + bx + c\] where a=5, b=30 and c=9

  92. Emmy82650
    • 2 years ago
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    thank you so much, i finally understand! :)

  93. Skaematik
    • 2 years ago
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    no problem :)

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