A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Hey, guys, I was wondering if you could help me with some statistics and physics. http://www.trin.cam.ac.uk/show.php?dowid=475 Questions 2, 4, 5, 6, 9 and 10. Thank you :)
 2 years ago
Hey, guys, I was wondering if you could help me with some statistics and physics. http://www.trin.cam.ac.uk/show.php?dowid=475 Questions 2, 4, 5, 6, 9 and 10. Thank you :)

This Question is Closed

Youngster
 2 years ago
Best ResponseYou've already chosen the best response.0for number two, make a "tree" i guess, it might help. sorry, im still learning statistics there is a formula for how to find the probablity of B given A, but I can't seem to get it on here. :(

mandja
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks nonetheless... :)

vf321
 2 years ago
Best ResponseYou've already chosen the best response.1@mandja for #2 what is the probability for a false positive? Are we to assume it is zero?

vf321
 2 years ago
Best ResponseYou've already chosen the best response.1Assuming that the test is 95% accurate for the positive and for 100% accurate for the negative, this is solvable: Let \(C\) denote having the condition and positive/negative signs denote the results. Given is this: \[P(C)=0.001\]\[P(+C) = 0.95\]\[P(\lnot C)=1P(C) = 0.999\]\[P(+\lnot C)=P(\lnot C\land+)/P(\lnot C)=0.05\]Then,\[P(C+)=\frac{P(+\land C)}{P(+)}\]Since \(P(+) = P(+\lnot C)P(\lnot C) + P(+C)P(C)\), we can just plug in the values to get: 1.8%

mandja
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks. For the 4th question I'm thinking of binomial distribution?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.