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mandja
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Hey, guys, I was wondering if you could help me with some statistics and physics. http://www.trin.cam.ac.uk/show.php?dowid=475 Questions 2, 4, 5, 6, 9 and 10. Thank you :)
 one year ago
 one year ago
mandja Group Title
Hey, guys, I was wondering if you could help me with some statistics and physics. http://www.trin.cam.ac.uk/show.php?dowid=475 Questions 2, 4, 5, 6, 9 and 10. Thank you :)
 one year ago
 one year ago

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Youngster Group TitleBest ResponseYou've already chosen the best response.0
for number two, make a "tree" i guess, it might help. sorry, im still learning statistics there is a formula for how to find the probablity of B given A, but I can't seem to get it on here. :(
 one year ago

mandja Group TitleBest ResponseYou've already chosen the best response.0
Thanks nonetheless... :)
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
@mandja for #2 what is the probability for a false positive? Are we to assume it is zero?
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Assuming that the test is 95% accurate for the positive and for 100% accurate for the negative, this is solvable: Let \(C\) denote having the condition and positive/negative signs denote the results. Given is this: \[P(C)=0.001\]\[P(+C) = 0.95\]\[P(\lnot C)=1P(C) = 0.999\]\[P(+\lnot C)=P(\lnot C\land+)/P(\lnot C)=0.05\]Then,\[P(C+)=\frac{P(+\land C)}{P(+)}\]Since \(P(+) = P(+\lnot C)P(\lnot C) + P(+C)P(C)\), we can just plug in the values to get: 1.8%
 one year ago

mandja Group TitleBest ResponseYou've already chosen the best response.0
Thanks. For the 4th question I'm thinking of binomial distribution?
 one year ago
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