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karatechopper

Circumcenter is the point P. Need to find segments congruent to line segment CS.

  • one year ago
  • one year ago

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  1. karatechopper
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    • one year ago
  2. karatechopper
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    Just need some assistance..please!

    • one year ago
  3. amistre64
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    congruent means "equal to" or equivalent

    • one year ago
  4. r0n4ld
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    the circumcenter is the point of concurrency of the three perpendicular bisectors (of the segments). The operative word here is bisector.

    • one year ago
  5. karatechopper
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    Yes. I know that,

    • one year ago
  6. amistre64
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    cant see the equation underneath so it difficult to see what the trianlge is spose to look like as opposed to its visual shape

    • one year ago
  7. karatechopper
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    Well its not an equation. They are just line segments

    • one year ago
  8. amistre64
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    its information pertaining to the shape that would help to define it otherwise it could just as well be an equilateral triangle

    • one year ago
  9. hartnn
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    since, PS is bisector, AS=CS

    • one year ago
  10. r0n4ld
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    since P is the circumcenter, it lies in the perpendicular BISECTOR BS

    • one year ago
  11. karatechopper
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    Yes, i have that segment down already. @hartnn

    • one year ago
  12. karatechopper
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    I am confused on that. You know i have to find congruent segments right? @r0n4ld

    • one year ago
  13. amistre64
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    at the moment, that is thhe only line segment that we can be sure of; the rest of the triangle is a mystery

    • one year ago
  14. karatechopper
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    Ok! Thats what i thought!

    • one year ago
  15. karatechopper
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    I was confused if there were any more thats why i posted

    • one year ago
  16. karatechopper
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    I have another question tho. Would line segment BT. be congruent to line segment BP?

    • one year ago
  17. hartnn
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    not at all, BP is hypotenuse of right triangle, whereas BT is the side.

    • one year ago
  18. hartnn
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    *BT is one of the leg.

    • one year ago
  19. karatechopper
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    Yes, but Point P is the circumcenter. So i would think every line segment is congruent.

    • one year ago
  20. karatechopper
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    If attached to Point P

    • one year ago
  21. hartnn
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    the 3 perpendicular bisectors will bisect 3 sides only... so u get 3 pirs of segments equal.

    • one year ago
  22. hartnn
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    *pairs

    • one year ago
  23. karatechopper
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    Would PS be one?

    • one year ago
  24. hartnn
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    nopes, because PS is not a part of a side of triangle.

    • one year ago
  25. hartnn
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    RA=RB SA=SC TB=TC

    • one year ago
  26. karatechopper
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    But they have to be congruent to BP

    • one year ago
  27. hartnn
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    there is a property : The perpendicular bisectors of the sides of a triangle meet at a point which is equidistant from the vertices so, BP=CP=AP also.

    • one year ago
  28. karatechopper
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    Oh..

    • one year ago
  29. karatechopper
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    BUT. P is the middle! So why wouldnt everyone thing attached to the P be congruent?

    • one year ago
  30. hartnn
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    u really can't say anything about PS,PT,PR

    • one year ago
  31. hartnn
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    'middle' doen;t mean middle of everything :P

    • one year ago
  32. hartnn
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    *doesn't

    • one year ago
  33. karatechopper
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    Awh man!

    • one year ago
  34. karatechopper
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    so its only CP and AP?

    • one year ago
  35. hartnn
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    yes...

    • one year ago
  36. hartnn
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    =BP

    • one year ago
  37. karatechopper
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    ok! THANKS!!!! :)

    • one year ago
  38. hartnn
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    welcome ^_^

    • one year ago
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