## karatechopper 3 years ago Circumcenter is the point P. Need to find segments congruent to line segment CS.

1. karatechopper

2. karatechopper

Just need some assistance..please!

3. amistre64

congruent means "equal to" or equivalent

4. r0n4ld

the circumcenter is the point of concurrency of the three perpendicular bisectors (of the segments). The operative word here is bisector.

5. karatechopper

Yes. I know that,

6. amistre64

cant see the equation underneath so it difficult to see what the trianlge is spose to look like as opposed to its visual shape

7. karatechopper

Well its not an equation. They are just line segments

8. amistre64

its information pertaining to the shape that would help to define it otherwise it could just as well be an equilateral triangle

9. hartnn

since, PS is bisector, AS=CS

10. r0n4ld

since P is the circumcenter, it lies in the perpendicular BISECTOR BS

11. karatechopper

Yes, i have that segment down already. @hartnn

12. karatechopper

I am confused on that. You know i have to find congruent segments right? @r0n4ld

13. amistre64

at the moment, that is thhe only line segment that we can be sure of; the rest of the triangle is a mystery

14. karatechopper

Ok! Thats what i thought!

15. karatechopper

I was confused if there were any more thats why i posted

16. karatechopper

I have another question tho. Would line segment BT. be congruent to line segment BP?

17. hartnn

not at all, BP is hypotenuse of right triangle, whereas BT is the side.

18. hartnn

*BT is one of the leg.

19. karatechopper

Yes, but Point P is the circumcenter. So i would think every line segment is congruent.

20. karatechopper

If attached to Point P

21. hartnn

the 3 perpendicular bisectors will bisect 3 sides only... so u get 3 pirs of segments equal.

22. hartnn

*pairs

23. karatechopper

Would PS be one?

24. hartnn

nopes, because PS is not a part of a side of triangle.

25. hartnn

RA=RB SA=SC TB=TC

26. karatechopper

But they have to be congruent to BP

27. hartnn

there is a property : The perpendicular bisectors of the sides of a triangle meet at a point which is equidistant from the vertices so, BP=CP=AP also.

28. karatechopper

Oh..

29. karatechopper

BUT. P is the middle! So why wouldnt everyone thing attached to the P be congruent?

30. hartnn

u really can't say anything about PS,PT,PR

31. hartnn

'middle' doen;t mean middle of everything :P

32. hartnn

*doesn't

33. karatechopper

Awh man!

34. karatechopper

so its only CP and AP?

35. hartnn

yes...

36. hartnn

=BP

37. karatechopper

ok! THANKS!!!! :)

38. hartnn

welcome ^_^