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karatechopper
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Circumcenter is the point P. Need to find segments congruent to line segment CS.
 one year ago
 one year ago
karatechopper Group Title
Circumcenter is the point P. Need to find segments congruent to line segment CS.
 one year ago
 one year ago

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karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Just need some assistance..please!
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
congruent means "equal to" or equivalent
 one year ago

r0n4ld Group TitleBest ResponseYou've already chosen the best response.0
the circumcenter is the point of concurrency of the three perpendicular bisectors (of the segments). The operative word here is bisector.
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Yes. I know that,
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
cant see the equation underneath so it difficult to see what the trianlge is spose to look like as opposed to its visual shape
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Well its not an equation. They are just line segments
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
its information pertaining to the shape that would help to define it otherwise it could just as well be an equilateral triangle
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
since, PS is bisector, AS=CS
 one year ago

r0n4ld Group TitleBest ResponseYou've already chosen the best response.0
since P is the circumcenter, it lies in the perpendicular BISECTOR BS
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Yes, i have that segment down already. @hartnn
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
I am confused on that. You know i have to find congruent segments right? @r0n4ld
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
at the moment, that is thhe only line segment that we can be sure of; the rest of the triangle is a mystery
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Ok! Thats what i thought!
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
I was confused if there were any more thats why i posted
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
I have another question tho. Would line segment BT. be congruent to line segment BP?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
not at all, BP is hypotenuse of right triangle, whereas BT is the side.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
*BT is one of the leg.
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Yes, but Point P is the circumcenter. So i would think every line segment is congruent.
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
If attached to Point P
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
the 3 perpendicular bisectors will bisect 3 sides only... so u get 3 pirs of segments equal.
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Would PS be one?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
nopes, because PS is not a part of a side of triangle.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
RA=RB SA=SC TB=TC
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
But they have to be congruent to BP
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
there is a property : The perpendicular bisectors of the sides of a triangle meet at a point which is equidistant from the vertices so, BP=CP=AP also.
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Oh..
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
BUT. P is the middle! So why wouldnt everyone thing attached to the P be congruent?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u really can't say anything about PS,PT,PR
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
'middle' doen;t mean middle of everything :P
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
Awh man!
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
so its only CP and AP?
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
ok! THANKS!!!! :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago
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