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karatechopper
 3 years ago
Circumcenter is the point P. Need to find segments congruent to line segment CS.
karatechopper
 3 years ago
Circumcenter is the point P. Need to find segments congruent to line segment CS.

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karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0Just need some assistance..please!

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1congruent means "equal to" or equivalent

r0n4ld
 3 years ago
Best ResponseYou've already chosen the best response.0the circumcenter is the point of concurrency of the three perpendicular bisectors (of the segments). The operative word here is bisector.

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0Yes. I know that,

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1cant see the equation underneath so it difficult to see what the trianlge is spose to look like as opposed to its visual shape

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0Well its not an equation. They are just line segments

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1its information pertaining to the shape that would help to define it otherwise it could just as well be an equilateral triangle

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1since, PS is bisector, AS=CS

r0n4ld
 3 years ago
Best ResponseYou've already chosen the best response.0since P is the circumcenter, it lies in the perpendicular BISECTOR BS

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, i have that segment down already. @hartnn

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0I am confused on that. You know i have to find congruent segments right? @r0n4ld

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1at the moment, that is thhe only line segment that we can be sure of; the rest of the triangle is a mystery

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0Ok! Thats what i thought!

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0I was confused if there were any more thats why i posted

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0I have another question tho. Would line segment BT. be congruent to line segment BP?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1not at all, BP is hypotenuse of right triangle, whereas BT is the side.

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, but Point P is the circumcenter. So i would think every line segment is congruent.

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0If attached to Point P

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1the 3 perpendicular bisectors will bisect 3 sides only... so u get 3 pirs of segments equal.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1nopes, because PS is not a part of a side of triangle.

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0But they have to be congruent to BP

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1there is a property : The perpendicular bisectors of the sides of a triangle meet at a point which is equidistant from the vertices so, BP=CP=AP also.

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0BUT. P is the middle! So why wouldnt everyone thing attached to the P be congruent?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1u really can't say anything about PS,PT,PR

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1'middle' doen;t mean middle of everything :P

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0so its only CP and AP?

karatechopper
 3 years ago
Best ResponseYou've already chosen the best response.0ok! THANKS!!!! :)
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