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Incenters. (Geometry) Have to find measures. Picture being uploaded.
 one year ago
 one year ago
Incenters. (Geometry) Have to find measures. Picture being uploaded.
 one year ago
 one year ago

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karatechopperBest ResponseYou've already chosen the best response.0
I am trying to fine AU. And Angle ARU. I think i have what i need for AU. Just need some confirmation.
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
Since TA is 20. I started thinking about the Bisecting thing. And I am saying that AU is also 20. Because KP bisects in Angle TAU
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
...Am i right on that?
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
yes, AU is 20, but how did u prove it ?
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
Well i kind of thought through it. Since the lesson is about Bisectors. I gave a thought that angle TAU was being bisected by KP. And if angle TAU was being bisected, and TA was 20; then AU must also be 20.
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
that can be proved by proving triangles congruent just saying will not be enough IF u need to show your work.
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
else reasoning is correct
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
Ok! And how should i figure out what the measure of angle ARU is? I am stuck there.
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
thats even simpler, AR bisects angle R
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
OH!!! SO then 40 degrees?
 one year ago
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