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fari321
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One factor of 4x^3+15x^231x30 is x2. Find the other factors
 one year ago
 one year ago
fari321 Group Title
One factor of 4x^3+15x^231x30 is x2. Find the other factors
 one year ago
 one year ago

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freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
You could use long division or synthetic division. Your choice.
 one year ago

fari321 Group TitleBest ResponseYou've already chosen the best response.0
with long division
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
Well to start with you know that \[4x^2 \times (x2) = 4x^38x^2\] so just like you would do long division with numbers you can also do it with variables like this. so \[ 4x^315x^2 \bigg[4x^38x^2 \bigg]=7x^2\] you drop the 31x like long division to get \[7x^2 31x\] and then divide this by (x2) again \[7x\times (x2) = 7x^2 +14x\] and so on
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
sorry the \[15x^2 \] should be positive 15
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
so \[4x^3+15x^2 \bigg[4x^38x^2 \bigg]=23x^2\] \[23x\times (x2) = 23x^246x\] \[23x^231x \bigg[23x^246x\bigg]=+15x\] \[15\times(x2)=15x30\] \[+15x30 \bigg[15x30 \bigg]=0\] so \[4x^3+15x^231x30 \to (x2)(4x^2+23x+15)\] and you can factor the rest... hopefully
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
Explaining how to do long division or synthetic division is a real pain on open study, I would suggest you take the time outside of this to study it from a book with examples. Or go online and search for a youtube video. It isn't hard.
 one year ago
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