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fari321
Group Title
One factor of 4x^3+15x^231x30 is x2. Find the other factors
 2 years ago
 2 years ago
fari321 Group Title
One factor of 4x^3+15x^231x30 is x2. Find the other factors
 2 years ago
 2 years ago

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freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
You could use long division or synthetic division. Your choice.
 2 years ago

fari321 Group TitleBest ResponseYou've already chosen the best response.0
with long division
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
Well to start with you know that \[4x^2 \times (x2) = 4x^38x^2\] so just like you would do long division with numbers you can also do it with variables like this. so \[ 4x^315x^2 \bigg[4x^38x^2 \bigg]=7x^2\] you drop the 31x like long division to get \[7x^2 31x\] and then divide this by (x2) again \[7x\times (x2) = 7x^2 +14x\] and so on
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
sorry the \[15x^2 \] should be positive 15
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
so \[4x^3+15x^2 \bigg[4x^38x^2 \bigg]=23x^2\] \[23x\times (x2) = 23x^246x\] \[23x^231x \bigg[23x^246x\bigg]=+15x\] \[15\times(x2)=15x30\] \[+15x30 \bigg[15x30 \bigg]=0\] so \[4x^3+15x^231x30 \to (x2)(4x^2+23x+15)\] and you can factor the rest... hopefully
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.0
Explaining how to do long division or synthetic division is a real pain on open study, I would suggest you take the time outside of this to study it from a book with examples. Or go online and search for a youtube video. It isn't hard.
 2 years ago
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