M, a solid cylinder (M=2.11 kg, R=0.137 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.870 kg mass, i.e., F = 8.535 N.
A. Calculate the angular acceleration of the cylinder.
For A. I got this and it's correct "59.0 rad/s^2"
B. If instead of the force F an actual mass m = 0.870 kg is hung from the string, find the angular acceleration of the cylinder.
C.How far does m travel downward between 0.670 s and 0.870 s after the motion begins

See more answers at brainly.com

Here is the Image of the figure!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.