M, a solid cylinder (M=2.11 kg, R=0.137 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.870 kg mass, i.e., F = 8.535 N.
A. Calculate the angular acceleration of the cylinder.
For A. I got this and it's correct "59.0 rad/s^2"
B. If instead of the force F an actual mass m = 0.870 kg is hung from the string, find the angular acceleration of the cylinder.
C.How far does m travel downward between 0.670 s and 0.870 s after the motion begins

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Here is the Image of the figure!

@Alonzo19

Looking for something else?

Not the answer you are looking for? Search for more explanations.