AmTran_Bus
Trig identities...harder one
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AmTran_Bus
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hba
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Try this. First, change all tan(x) and cot(x) into sin(x)/cos(x) and cos(x)/sin(x) respectively. Then combine the fractions using common denominator which is cos(x)sin(x).
-Hba.
hba
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@AmTran_Bus Try it and tell me what you get ?
AmTran_Bus
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I kept getting it to equal sin2. Let me give it another try.
hba
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No if you try to reduce it,It will come to
\[ \sin^2x -\cos^2x \]
AmTran_Bus
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Agreed. I see you now. I have it on my paper. But now you have your +2cos^2 on there. I know sin+cos=1 (as long as they are both squared)...but what about the rest?
hba
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Then put it in the actual ques.
\[\sin^2x- \cos^2x + 2\cos^2x = 1\]
hba
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Now you know how it goes ? @AmTran_Bus
AmTran_Bus
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I understand that, yes. But maybe I just can't see it because I can't carry it on.
hba
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AmTran_Bus
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hba
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AmTran_Bus
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Oh yes. Thanks and Happy Thanksgiving.
hba
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