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Trig identities...harder one

Mathematics
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  • hba
Try this. First, change all tan(x) and cot(x) into sin(x)/cos(x) and cos(x)/sin(x) respectively. Then combine the fractions using common denominator which is cos(x)sin(x). -Hba.
  • hba
@AmTran_Bus Try it and tell me what you get ?

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Other answers:

I kept getting it to equal sin2. Let me give it another try.
  • hba
No if you try to reduce it,It will come to \[ \sin^2x -\cos^2x \]
Agreed. I see you now. I have it on my paper. But now you have your +2cos^2 on there. I know sin+cos=1 (as long as they are both squared)...but what about the rest?
  • hba
Then put it in the actual ques. \[\sin^2x- \cos^2x + 2\cos^2x = 1\]
  • hba
Now you know how it goes ? @AmTran_Bus
I understand that, yes. But maybe I just can't see it because I can't carry it on.
  • hba
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  • hba
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Oh yes. Thanks and Happy Thanksgiving.
  • hba
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