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scotth

  • 2 years ago

one mole each of acetic acid and ethyl alcohol are mixed at 25'c .when the mixture attains equilibrium it is found tht 12g of water formed .find the value of kc what weight of ethyl acetate will be formed when 2mole of ethyl alcohol are further added and the equlibrium is attained?

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  1. scotth
    • 2 years ago
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    @saifoo.khan

  2. saifoo.khan
    • 2 years ago
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    This one's hard. :O

  3. saifoo.khan
    • 2 years ago
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    |dw:1353640945617:dw|

  4. scotth
    • 2 years ago
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    ch3cooh + c2h5oh= ch3cooc2h5+h2o am i right?

  5. saifoo.khan
    • 2 years ago
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    Moles of water = mass/Mr = 12/(18) = 0.67 mol |dw:1353641101763:dw|

  6. saifoo.khan
    • 2 years ago
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    |dw:1353641191133:dw|

  7. saifoo.khan
    • 2 years ago
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    And yes, your equation is correct.

  8. saifoo.khan
    • 2 years ago
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    Since we don't know the volume, take it as v. Using the formula n = cv |dw:1353641335774:dw|