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i know that much i did that too didnt get the answer though

i have to give the answer is "%" change

Ok we ll work towards it don't worry.. !

answer my question first :P

6400/6080 ?

:O.. no.. how did you get that? :-/

listen .. use the equation of g..

\[\frac{95}{100} \times 6400\]

New one^^

yes.. but i want the value of g.. not the radius!

\[g= \frac{GM}{R ^{2}}\]

R'=95/100R

yes exactly.. now put the new value of R .. and get the ratio!!

20GM/19R is the new one? :S

if you plug in the values.. you should get
g (prime)/ g = 1.108

yeah..okay

so 11%?

10.8 percent..

11.08%?

no.. see.. the increase is .108 ( 1.108-1) ... hence percent is 10.8!

okayy

answer is 10% though!

wait . lemme see if i did some calc. mistake!

the solution is solved using differentiation n stuff

!? :-/ why differentiation? :O :O

DK

\[\frac{dg}{dR} = \frac{d}{dR} ( \frac {GM}{R ^{2}} ) = GM \frac{d}{dR} (R^{-2}) \]

Solving this we got,
\[\frac{-2g}{r}\]

ohh.. like that.. ! thats not really required!!

dg/g=-2dR/R

:O

at last we get 0.1*100=10%!!

i find no flaw in calc.. i dunno really what went wrong :-/

aha i get it now.. thanks .. ! :)

hence differentiation is used for instantaneous change right?!...