Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

hbaBest ResponseYou've already chosen the best response.8
\[\Huge{\bf{Law\ of\ Logaritm:}}\] \[1.\log _{_{a}}a(xy)=\log _{_{a}}x+\log _{a}y\]\[2.\log_a \ (\frac{ x }{ y })=\log_ax\log_ay\]\[3.\log_ax^m=mlog_ax\]
 one year ago

hbaBest ResponseYou've already chosen the best response.8
\[\Huge{\bf{CHANGE\ OF \ BASE \ OF \ LOG:}}\] \[\log_aN=\frac{ \log_mN }{ \log_ma }\]
 one year ago

hbaBest ResponseYou've already chosen the best response.8
\[\Huge{\bf{SOME\ USEFUL\ RESULTS:}}\] \[1.\log_aa=1\]\[2.\log_a1=0\]\[3.\log_a0=\infty \]\[4.\log_ab*\log_ca=\log_cb\]\[5.a^{\log_a^n}=n\]In particular,\[e^{lnn}=n\]\[6.\log_ab=\frac{ 1 }{ \log _{a}^{b} } or\ \log_ab*\log_ba=1\]
 one year ago

hbaBest ResponseYou've already chosen the best response.8
@ash2326 @Agent_Sniffles @AccessDenied @cwrw238 @ganeshie8 @him1618 @mayankdevnani @nitz @nubeer @Skaematik @Spectrum
 one year ago

mayankdevnaniBest ResponseYou've already chosen the best response.0
\[\Huge{\color{red}{thnx...} \space \color{blue}{@hba!!!}}\] \[\Huge{\color{green}{\ddot \smile}} \]
 one year ago

mayankdevnaniBest ResponseYou've already chosen the best response.0
\[\huge{\color{red}{\frak{ \space \text{great} \space tutorial \space}\mathbb{Thanx !!!!!!}}}\]
 one year ago

SpectrumBest ResponseYou've already chosen the best response.0
@hba why didy ou do this ..i have a headache now ._. :3
 one year ago

hbaBest ResponseYou've already chosen the best response.8
@Spectrum I am sorry but i tried my best to simplify it.
 one year ago

SpectrumBest ResponseYou've already chosen the best response.0
haha im kidding man :3.gj medal for you
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
log 0 = infinity ??maybe you mean infinity.. anyways, i'd say that's neither..its undefined..
 one year ago

hbaBest ResponseYou've already chosen the best response.8
I know i have read this and it can be either + infty or  infty so as we are not sure,I may go with Undefined,Thanks for the feedback.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
log 0 is undefined but if we have to choose from +inf and inf, it would definitely be inf. a^inf =0 doesn't make sense, inf is very large number, a^inf also is. a^inf =0 makes sense, more appropriately, its very very small number tending to 0.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
he wrote my mind down! :P
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
you realize, u have a typo in 1. @hba
 one year ago

hbaBest ResponseYou've already chosen the best response.8
Oh man,how can i make mistakes :(
 one year ago

hbaBest ResponseYou've already chosen the best response.8
@hartnn Thanks for the feedback though.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
i tried to message you, but u won't accept....
 one year ago

hbaBest ResponseYou've already chosen the best response.8
@hartnn Don't worry i am going to make a correction slot.
 one year ago

hbaBest ResponseYou've already chosen the best response.8
\[\Huge{\bf{CORRECTIONS:}}\] The first law of log  \[1.\log _{_{a}}(xy)=\log _{_{a}}x+\log _{a}y\] The useful result area  \[3.\log_a0= Undefined\]
 one year ago

hbaBest ResponseYou've already chosen the best response.8
\[\frak\color{red}{oh\ oooooooooooo}\]
 one year ago

hbaBest ResponseYou've already chosen the best response.8
@hartnn Do you know something which everyone is looking for because i want to make more tutorials ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
if i would've known, i would've made tutorial :P
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.