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hba

Logarithm-a log sheet to help you guys.

  • one year ago
  • one year ago

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  1. hba
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    \[\Huge{\bf{Law\ of\ Logaritm:}}\] \[1.\log _{_{a}}a(xy)=\log _{_{a}}x+\log _{a}y\]\[2.\log_a \ (\frac{ x }{ y })=\log_ax-\log_ay\]\[3.\log_ax^m=mlog_ax\]

    • one year ago
  2. hba
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    \[\Huge{\bf{CHANGE\ OF \ BASE \ OF \ LOG:}}\] \[\log_aN=\frac{ \log_mN }{ \log_ma }\]

    • one year ago
  3. hba
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    \[\Huge{\bf{SOME\ USEFUL\ RESULTS:}}\] \[1.\log_aa=1\]\[2.\log_a1=0\]\[3.\log_a0=\infty \]\[4.\log_ab*\log_ca=\log_cb\]\[5.a^{\log_a^n}=n\]In particular,\[e^{lnn}=n\]\[6.\log_ab=\frac{ 1 }{ \log _{a}^{b} } or\ \log_ab*\log_ba=1\]

    • one year ago
  4. hba
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    @ash2326 @Agent_Sniffles @AccessDenied @cwrw238 @ganeshie8 @him1618 @mayankdevnani @nitz @nubeer @Skaematik @Spectrum

    • one year ago
  5. mayankdevnani
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    \[\Huge{\color{red}{thnx...} \space \color{blue}{@hba!!!}}\] \[\Huge{\color{green}{\ddot \smile}} \]

    • one year ago
  6. mayankdevnani
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    \[\huge{\color{red}{\frak{ \space \text{great} \space tutorial \space}\mathbb{Thanx !!!!!!}}}\]

    • one year ago
  7. nitz
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    good job!

    • one year ago
  8. hba
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    Thanks a lot guys.

    • one year ago
  9. mayankdevnani
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    welcome!!

    • one year ago
  10. Spectrum
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    @hba why didy ou do this ..i have a headache now ._. :3

    • one year ago
  11. hba
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    @Spectrum I am sorry but i tried my best to simplify it.

    • one year ago
  12. Spectrum
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    haha im kidding man :3.gj medal for you

    • one year ago
  13. hba
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    Thanks a lot.

    • one year ago
  14. shubhamsrg
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    log 0 = infinity ??maybe you mean -infinity.. anyways, i'd say that's neither..its undefined..

    • one year ago
  15. hba
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    no, log_{a}0 =infty

    • one year ago
  16. shubhamsrg
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    any valid reason ?

    • one year ago
  17. hba
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    I know i have read this and it can be either + infty or - infty so as we are not sure,I may go with Undefined,Thanks for the feedback.

    • one year ago
  18. shubhamsrg
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    hmm..

    • one year ago
  19. hartnn
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    log 0 is undefined but if we have to choose from +inf and -inf, it would definitely be -inf. a^inf =0 doesn't make sense, inf is very large number, a^inf also is. a^-inf =0 makes sense, more appropriately, its very very small number tending to 0.

    • one year ago
  20. shubhamsrg
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    he wrote my mind down! :P

    • one year ago
  21. shubhamsrg
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    i mean you*`

    • one year ago
  22. hartnn
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    you realize, u have a typo in 1. @hba

    • one year ago
  23. hartnn
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    an extra a.

    • one year ago
  24. hba
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    Oh man,how can i make mistakes :(

    • one year ago
  25. hba
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    @hartnn Thanks for the feedback though.

    • one year ago
  26. hartnn
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    i tried to message you, but u won't accept....

    • one year ago
  27. hba
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    @hartnn Don't worry i am going to make a correction slot.

    • one year ago
  28. hba
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    \[\Huge{\bf{CORRECTIONS:}}\] The first law of log --------------- \[1.\log _{_{a}}(xy)=\log _{_{a}}x+\log _{a}y\] The useful result area ------------------ \[3.\log_a0= Undefined\]

    • one year ago
  29. hba
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    @hartnn What say ?

    • one year ago
  30. hartnn
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    i say 'Good Work' :)

    • one year ago
  31. hba
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    Thanks :)

    • one year ago
  32. hba
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    @lalaly

    • one year ago
  33. hba
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    \[\frak\color{red}{oh\ oooooooooooo}\]

    • one year ago
  34. hba
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    @hartnn Do you know something which everyone is looking for because i want to make more tutorials ?

    • one year ago
  35. hartnn
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    if i would've known, i would've made tutorial :P

    • one year ago
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