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Spectrum

  • 3 years ago

sin(a-b) = sinacosb+cosasinb for all values of a and b. True or false?

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  1. g152xx
    • 3 years ago
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    False.

  2. Spectrum
    • 3 years ago
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    evidence?

  3. g152xx
    • 3 years ago
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    It should be sin(a - b) = sin(a)cos(b) - cos(a)sin(b)

  4. g152xx
    • 3 years ago
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    Let's do it this way to evidence more: sin(a - b) = sin(a)cos(b) - sin(b)cos(a) sin(a + b) = sin(a)cos(b) + sin(b)cos(a) SO, cos(a - b) = cos(a)cos(b) + sin(a)sin(b) cos(a + b) = cos(a)cos(b) - sin(a)sin(b) Simple.

  5. g152xx
    • 3 years ago
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    Thank you @Praja_01

  6. g152xx
    • 3 years ago
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    Thank you very much @Spectrum.

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