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@Skaematik Can't we use a formula there ?

What formula

L(x) = f(a) + f'(a)(x-a)

Formula to expand (x^2+3)^2
(a+b)^2=a^2+2ab+b^2

f(a)= (a^3 - 2a + 4)^2
then,
f'(a)= ?
Diffrentiate f(a) and find f'(a)

Why cant you just expand and take the natural log of both sides?

I am not sure about your input @Skaematik

@Pauloading Did you differentiate it ?

I imagine it's: f'(a) = 2.(3x^2 - 2.1 + 0), right?

I imagine that its f'(a) not f'(x)

@Pauloading do you follow @Skaematik Method ?

Not yet :x

@Pauloading Do you want to follow my method ?

I'ts sound like greek to me :'(
I'm really bad on it.

@g152xx I hope you can help @Pauloading ,i gotta go workout ?

@Pauloading Bump the question! Let's help him ppl! C'mon!

How did u get 6 at f'?

could you find f'(x) =... ?

I asked her the same thing before :D

I got 2.(3x^2 - 2)

no, thats not correct... u need chain rule.

hm....got it

ok, what u got f'(x) =... ?

The answer would be 2 (-2 + 3 a^2) (4 - 2 a + a^3)

let me verify it for you....

Now I understood it '-'
Thanks everyone :D

was that ^ copied ?

from wolf ?

Yeah :D

gotcha.....

I had to show her how to do it :)

him*

okay.
welcome paul ^_^

Paulo*

Thanks >.<

Your'e Welcome.

LoL :D

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