A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
(10^25)7 is divisible by
a) 2 b)3 c)9 d) both 2 & 3
anonymous
 4 years ago
(10^25)7 is divisible by a) 2 b)3 c)9 d) both 2 & 3

This Question is Open

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.010^25=10000000000000000000000000 the number is not so important u know that the last digit will be 0 and is u substract 7 u will have tha last digit 3 si it is divisible by 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0107=3 therefore 10^257 is divisible by 3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its not last digit but all preceeding digits are 9. therefore sum of 23 9s+3 is a multiple of 3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if u have 10 or 10^2 meaning 100 or 10^x it doesn't matter cause by substracting 7 u will have the last digit 3 and 3 is divisible only with 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0133 for instance is not divisible by 3.

shubhamsrg
 4 years ago
Best ResponseYou've already chosen the best response.0anyways,alternately, we know, 10^n = 3q + 1 and 7 = 3p + 1 subtracting both, 10^n  7 = 3(qp) = 3r ==> divisible by 3
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.