Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

prove that x²+2xy+3y²≥0 for all x, y E R

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
hint: Expand \((x+y)^2\)
i'm sorry i'm still lost
what can you say about the number \((x+y)^2\)? can it ever be negative?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

yes
how?
remember x, y E R
well i thought anything squared would be true bit i can't get the two brackets the same as i can't get 3y squared
try and first expand \((x+y)^2\) and then see what else you need to add to this in order to get your original expression of \(x^2+2xy+3y^2\)
so the answere would be (x+y)^2 + y^2
not quite - what do you get when you expand \((x+y)^2\) ?
(x+y)^2+2y^2
x^2 + 2xy + y ^2
correct - now what do you need to add to this in order to get to your original expression?
2y to be squared
perfect!
so we end up with:\[x^2+2xy+3y^2=(x+y)^2+2y^2\]now - can you see that this can never be negative?
ok thanks while i have you i have to do this using the same axsis and scales graph the functions f(x)=|x| and g(x)= |2x - 3|
yw :) could you please post that as a separate question. thanks.
using the same axsis and scales graph the functions f(x)=|x| and g(x)= |2x - 3|
<--- I meant post in the list to the left
oh ok sorry
np :) it just helps posting each question separately as others can then see each question more easily and also learn from them. :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question