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samnatha

  • 2 years ago

using the same axsis and scales graph the functions f(x)=|x| and g(x)= |2x - 3|

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  1. mathstudent55
    • 2 years ago
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    Make a table of values for each function. To do that, come up with some values for x and calculate f(x) and g(x) f(x) = |x| x | f(x) ---------- -2 | 2 -1 | 1 0 | 0 1 | 1 2 | 2 Use the above points to graph f(x). Then do the same for G(X)

  2. Aperogalics
    • 2 years ago
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    @samnatha r u there?????/

  3. samnatha
    • 2 years ago
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    yes sorry was just tying to work it out

  4. samnatha
    • 2 years ago
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    i then have to solve |x| = | 2x-3|

  5. samnatha
    • 2 years ago
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    is anyone there ?

  6. mathstudent55
    • 2 years ago
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    No. You don't need to solve that equation. Just make two tables of points and graph both on the same x-y graph

  7. samnatha
    • 2 years ago
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    oh ok thanks theres another one which is |2x-3| < |x|

  8. mathstudent55
    • 2 years ago
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    Sorry, I misread your post. When you said you have to solve |x| = |2x - 3|. I thought you meant that you needed to solve that to get the graph. After you graph both f(x) and g(x on the same graph, see where the graphs intersect. That's the solution to|x| = |2x - 3|

  9. samnatha
    • 2 years ago
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    ok thanks i got that bit but i'm not too sure on the second bit

  10. mathstudent55
    • 2 years ago
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    |dw:1353697888667:dw|

  11. mathstudent55
    • 2 years ago
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    The soulition to |x| = |2x - 3| is where the two graphs intersect. There are two points.

  12. samnatha
    • 2 years ago
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    (1,1) and (3.5, 3.5) thats what i got on my graph is that right ?

  13. mathstudent55
    • 2 years ago
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    The solution to |2x - 3| < |x| is the x values for which the value of g(x) is less than the value of f(x). If you look in graph, see where the y vaslue of g(x) is lower than the y value of f(x).

  14. mathstudent55
    • 2 years ago
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    I think it's (1,1) and (3,3)

  15. samnatha
    • 2 years ago
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    ok my graph is probs a bit diff but thanks for your help :)

  16. mathstudent55
    • 2 years ago
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    You're welcome

  17. samnatha
    • 2 years ago
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    god the pressures of leaving cert math

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