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samnatha Group Title

using the same axsis and scales graph the functions f(x)=|x| and g(x)= |2x - 3|

  • one year ago
  • one year ago

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  1. mathstudent55 Group Title
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    Make a table of values for each function. To do that, come up with some values for x and calculate f(x) and g(x) f(x) = |x| x | f(x) ---------- -2 | 2 -1 | 1 0 | 0 1 | 1 2 | 2 Use the above points to graph f(x). Then do the same for G(X)

    • one year ago
  2. Aperogalics Group Title
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    @samnatha r u there?????/

    • one year ago
  3. samnatha Group Title
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    yes sorry was just tying to work it out

    • one year ago
  4. samnatha Group Title
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    i then have to solve |x| = | 2x-3|

    • one year ago
  5. samnatha Group Title
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    is anyone there ?

    • one year ago
  6. mathstudent55 Group Title
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    No. You don't need to solve that equation. Just make two tables of points and graph both on the same x-y graph

    • one year ago
  7. samnatha Group Title
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    oh ok thanks theres another one which is |2x-3| < |x|

    • one year ago
  8. mathstudent55 Group Title
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    Sorry, I misread your post. When you said you have to solve |x| = |2x - 3|. I thought you meant that you needed to solve that to get the graph. After you graph both f(x) and g(x on the same graph, see where the graphs intersect. That's the solution to|x| = |2x - 3|

    • one year ago
  9. samnatha Group Title
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    ok thanks i got that bit but i'm not too sure on the second bit

    • one year ago
  10. mathstudent55 Group Title
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    |dw:1353697888667:dw|

    • one year ago
  11. mathstudent55 Group Title
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    The soulition to |x| = |2x - 3| is where the two graphs intersect. There are two points.

    • one year ago
  12. samnatha Group Title
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    (1,1) and (3.5, 3.5) thats what i got on my graph is that right ?

    • one year ago
  13. mathstudent55 Group Title
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    The solution to |2x - 3| < |x| is the x values for which the value of g(x) is less than the value of f(x). If you look in graph, see where the y vaslue of g(x) is lower than the y value of f(x).

    • one year ago
  14. mathstudent55 Group Title
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    I think it's (1,1) and (3,3)

    • one year ago
  15. samnatha Group Title
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    ok my graph is probs a bit diff but thanks for your help :)

    • one year ago
  16. mathstudent55 Group Title
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    You're welcome

    • one year ago
  17. samnatha Group Title
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    god the pressures of leaving cert math

    • one year ago
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