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samnatha Group Title

using the same axsis and scales graph the functions f(x)=|x| and g(x)= |2x - 3|

  • 2 years ago
  • 2 years ago

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  1. mathstudent55 Group Title
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    Make a table of values for each function. To do that, come up with some values for x and calculate f(x) and g(x) f(x) = |x| x | f(x) ---------- -2 | 2 -1 | 1 0 | 0 1 | 1 2 | 2 Use the above points to graph f(x). Then do the same for G(X)

    • 2 years ago
  2. Aperogalics Group Title
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    @samnatha r u there?????/

    • 2 years ago
  3. samnatha Group Title
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    yes sorry was just tying to work it out

    • 2 years ago
  4. samnatha Group Title
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    i then have to solve |x| = | 2x-3|

    • 2 years ago
  5. samnatha Group Title
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    is anyone there ?

    • 2 years ago
  6. mathstudent55 Group Title
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    No. You don't need to solve that equation. Just make two tables of points and graph both on the same x-y graph

    • 2 years ago
  7. samnatha Group Title
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    oh ok thanks theres another one which is |2x-3| < |x|

    • 2 years ago
  8. mathstudent55 Group Title
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    Sorry, I misread your post. When you said you have to solve |x| = |2x - 3|. I thought you meant that you needed to solve that to get the graph. After you graph both f(x) and g(x on the same graph, see where the graphs intersect. That's the solution to|x| = |2x - 3|

    • 2 years ago
  9. samnatha Group Title
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    ok thanks i got that bit but i'm not too sure on the second bit

    • 2 years ago
  10. mathstudent55 Group Title
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    |dw:1353697888667:dw|

    • 2 years ago
  11. mathstudent55 Group Title
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    The soulition to |x| = |2x - 3| is where the two graphs intersect. There are two points.

    • 2 years ago
  12. samnatha Group Title
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    (1,1) and (3.5, 3.5) thats what i got on my graph is that right ?

    • 2 years ago
  13. mathstudent55 Group Title
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    The solution to |2x - 3| < |x| is the x values for which the value of g(x) is less than the value of f(x). If you look in graph, see where the y vaslue of g(x) is lower than the y value of f(x).

    • 2 years ago
  14. mathstudent55 Group Title
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    I think it's (1,1) and (3,3)

    • 2 years ago
  15. samnatha Group Title
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    ok my graph is probs a bit diff but thanks for your help :)

    • 2 years ago
  16. mathstudent55 Group Title
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    You're welcome

    • 2 years ago
  17. samnatha Group Title
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    god the pressures of leaving cert math

    • 2 years ago
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