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iop360 Group Title

solve for z, and give your answer in the form a + bi (conj)z+2z = 2+4i+conj(7+3i) **conj refers to conjugate of a complex number (a line on top of it)

  • 2 years ago
  • 2 years ago

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  1. iop360 Group Title
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    answer is 3+i (need to learn how to do it)

    • 2 years ago
  2. math>philosophy Group Title
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    I don't understand the notation of the equation. Why did you put (conj)? Does it mean take the conjugate of the term that follows it? Or multiply that term by its conjugate? Or what?

    • 2 years ago
  3. iop360 Group Title
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    i dont know how to write a line above the letter for this

    • 2 years ago
  4. iop360 Group Title
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    so for this question, there would be a line above the z and the 7+3i

    • 2 years ago
  5. iop360 Group Title
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    z = a + bi (conj)z = a - bi

    • 2 years ago
  6. iop360 Group Title
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    it means to flip the sign of the imaginary part

    • 2 years ago
  7. math>philosophy Group Title
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    So why don't you just write z - 2z = 2 + 4i + (7 - 3i)? Is that what the question says?

    • 2 years ago
  8. iop360 Group Title
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    no, there is no line above the z+2z, just the z

    • 2 years ago
  9. math>philosophy Group Title
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    Can you draw the question instead?

    • 2 years ago
  10. iop360 Group Title
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    |dw:1353720314063:dw|

    • 2 years ago
  11. tkhunny Group Title
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    \(\bar{z} + 2z = 2 + 4i + \overline{7+3i} = 2 + 4i + 7 - 3i = 9 + i\)

    • 2 years ago
  12. iop360 Group Title
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    answer is 3+i though...you seem to be on the right track though

    • 2 years ago
  13. math>philosophy Group Title
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    no idea what the conjugate of a variable means...

    • 2 years ago
  14. math>philosophy Group Title
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    unless you use fourier which i don't think you are

    • 2 years ago
  15. tkhunny Group Title
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    It's not my problem statement. You need to be on the right track. Where shall we go from here? \(\bar{z} + 2z = 9 + i\)

    • 2 years ago
  16. iop360 Group Title
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    i dont know what the z part is. that is the problem

    • 2 years ago
  17. iop360 Group Title
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    is z considered real or imaginary?

    • 2 years ago
  18. iop360 Group Title
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    i tried it with both for hours

    • 2 years ago
  19. tkhunny Group Title
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    Please read the problem statement. "solve for z, and give your answer in the form a + bi" z is a Complex Number

    • 2 years ago
  20. math>philosophy Group Title
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    oh

    • 2 years ago
  21. tkhunny Group Title
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    You tried what? \(\bar{z} + 2z = a - bi + 2(a + bi) = a - bi + 2a + 2bi = (a + 2a) + (2b-b)i\) Do yuo see where this is going?

    • 2 years ago
  22. iop360 Group Title
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    no

    • 2 years ago
  23. iop360 Group Title
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    i understand why you get this but why did you do this

    • 2 years ago
  24. iop360 Group Title
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    you equate this to 9+i?

    • 2 years ago
  25. tkhunny Group Title
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    That is it! \(3a + bi = 9 + i\)

    • 2 years ago
  26. iop360 Group Title
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    thanks

    • 2 years ago
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