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iop360

  • 2 years ago

solve for z, and give your answer in the form a + bi (conj)z+2z = 2+4i+conj(7+3i) **conj refers to conjugate of a complex number (a line on top of it)

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  1. iop360
    • 2 years ago
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    answer is 3+i (need to learn how to do it)

  2. math>philosophy
    • 2 years ago
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    I don't understand the notation of the equation. Why did you put (conj)? Does it mean take the conjugate of the term that follows it? Or multiply that term by its conjugate? Or what?

  3. iop360
    • 2 years ago
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    i dont know how to write a line above the letter for this

  4. iop360
    • 2 years ago
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    so for this question, there would be a line above the z and the 7+3i

  5. iop360
    • 2 years ago
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    z = a + bi (conj)z = a - bi

  6. iop360
    • 2 years ago
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    it means to flip the sign of the imaginary part

  7. math>philosophy
    • 2 years ago
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    So why don't you just write z - 2z = 2 + 4i + (7 - 3i)? Is that what the question says?

  8. iop360
    • 2 years ago
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    no, there is no line above the z+2z, just the z

  9. math>philosophy
    • 2 years ago
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    Can you draw the question instead?

  10. iop360
    • 2 years ago
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    |dw:1353720314063:dw|

  11. tkhunny
    • 2 years ago
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    \(\bar{z} + 2z = 2 + 4i + \overline{7+3i} = 2 + 4i + 7 - 3i = 9 + i\)

  12. iop360
    • 2 years ago
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    answer is 3+i though...you seem to be on the right track though

  13. math>philosophy
    • 2 years ago
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    no idea what the conjugate of a variable means...

  14. math>philosophy
    • 2 years ago
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    unless you use fourier which i don't think you are

  15. tkhunny
    • 2 years ago
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    It's not my problem statement. You need to be on the right track. Where shall we go from here? \(\bar{z} + 2z = 9 + i\)

  16. iop360
    • 2 years ago
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    i dont know what the z part is. that is the problem

  17. iop360
    • 2 years ago
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    is z considered real or imaginary?

  18. iop360
    • 2 years ago
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    i tried it with both for hours

  19. tkhunny
    • 2 years ago
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    Please read the problem statement. "solve for z, and give your answer in the form a + bi" z is a Complex Number

  20. math>philosophy
    • 2 years ago
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    oh

  21. tkhunny
    • 2 years ago
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    You tried what? \(\bar{z} + 2z = a - bi + 2(a + bi) = a - bi + 2a + 2bi = (a + 2a) + (2b-b)i\) Do yuo see where this is going?

  22. iop360
    • 2 years ago
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    no

  23. iop360
    • 2 years ago
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    i understand why you get this but why did you do this

  24. iop360
    • 2 years ago
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    you equate this to 9+i?

  25. tkhunny
    • 2 years ago
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    That is it! \(3a + bi = 9 + i\)

  26. iop360
    • 2 years ago
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    thanks

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