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anonymous
 3 years ago
solve for z, and give your answer in the form a + bi
(conj)z+2z = 2+4i+conj(7+3i)
**conj refers to conjugate of a complex number
(a line on top of it)
anonymous
 3 years ago
solve for z, and give your answer in the form a + bi (conj)z+2z = 2+4i+conj(7+3i) **conj refers to conjugate of a complex number (a line on top of it)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0answer is 3+i (need to learn how to do it)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't understand the notation of the equation. Why did you put (conj)? Does it mean take the conjugate of the term that follows it? Or multiply that term by its conjugate? Or what?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know how to write a line above the letter for this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so for this question, there would be a line above the z and the 7+3i

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0z = a + bi (conj)z = a  bi

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it means to flip the sign of the imaginary part

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So why don't you just write z  2z = 2 + 4i + (7  3i)? Is that what the question says?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, there is no line above the z+2z, just the z

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you draw the question instead?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353720314063:dw

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.2\(\bar{z} + 2z = 2 + 4i + \overline{7+3i} = 2 + 4i + 7  3i = 9 + i\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0answer is 3+i though...you seem to be on the right track though

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no idea what the conjugate of a variable means...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0unless you use fourier which i don't think you are

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.2It's not my problem statement. You need to be on the right track. Where shall we go from here? \(\bar{z} + 2z = 9 + i\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know what the z part is. that is the problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is z considered real or imaginary?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i tried it with both for hours

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.2Please read the problem statement. "solve for z, and give your answer in the form a + bi" z is a Complex Number

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.2You tried what? \(\bar{z} + 2z = a  bi + 2(a + bi) = a  bi + 2a + 2bi = (a + 2a) + (2bb)i\) Do yuo see where this is going?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i understand why you get this but why did you do this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you equate this to 9+i?

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.2That is it! \(3a + bi = 9 + i\)
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