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answer is 3+i (need to learn how to do it)

i dont know how to write a line above the letter for this

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so for this question, there would be a line above the z and the 7+3i

z = a + bi
(conj)z = a - bi

it means to flip the sign of the imaginary part

So why don't you just write z - 2z = 2 + 4i + (7 - 3i)? Is that what the question says?

no, there is no line above the z+2z, just the z

Can you draw the question instead?

|dw:1353720314063:dw|

\(\bar{z} + 2z = 2 + 4i + \overline{7+3i} = 2 + 4i + 7 - 3i = 9 + i\)

answer is 3+i though...you seem to be on the right track though

no idea what the conjugate of a variable means...

unless you use fourier which i don't think you are

i dont know what the z part is. that is the problem

is z considered real or imaginary?

i tried it with both for hours

oh

no

i understand why you get this but why did you do this

you equate this to 9+i?

That is it! \(3a + bi = 9 + i\)

thanks

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