## anonymous 3 years ago find the exact area of the region enclosed by the graph of y=3-2x^2, the lines x=1 and x=-1, and the x axis

1. anonymous

use integration

2. anonymous

$\int\limits_{}^{}3-2x ^{2} = 3x-2/3x ^{3}$

3. anonymous

But then what do i do? Do i input x=1 x=-1?

4. anonymous

Do you know fundamental theorem: F(b) - F(a) = F(1) - F (-1)

5. anonymous

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6. anonymous

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7. anonymous

Ok yes....so.... $[3(1)-\left(\begin{matrix}2 \\ 3\end{matrix}\right)(1)^{3}] - [3(-1)-\frac{ 2 }{ 3 }(-1)^{3}$ =14/3

8. anonymous

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9. anonymous

10. anonymous

no

11. anonymous

ok thank you!