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marnie12345

  • 3 years ago

find the exact area of the region enclosed by the graph of y=3-2x^2, the lines x=1 and x=-1, and the x axis

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  1. math>philosophy
    • 3 years ago
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    use integration

  2. marnie12345
    • 3 years ago
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    \[\int\limits_{}^{}3-2x ^{2} = 3x-2/3x ^{3}\]

  3. marnie12345
    • 3 years ago
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    But then what do i do? Do i input x=1 x=-1?

  4. Chlorophyll
    • 3 years ago
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    Do you know fundamental theorem: F(b) - F(a) = F(1) - F (-1)

  5. cinar
    • 3 years ago
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    |dw:1353720420678:dw|

  6. cinar
    • 3 years ago
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    |dw:1353720574169:dw|

  7. marnie12345
    • 3 years ago
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    Ok yes....so.... \[[3(1)-\left(\begin{matrix}2 \\ 3\end{matrix}\right)(1)^{3}] - [3(-1)-\frac{ 2 }{ 3 }(-1)^{3}\] =14/3

  8. cinar
    • 3 years ago
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    |dw:1353720631909:dw|

  9. marnie12345
    • 3 years ago
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    Would I add the + C in my answer?

  10. cinar
    • 3 years ago
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    no

  11. marnie12345
    • 3 years ago
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    ok thank you!

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