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meww
Group Title
Convert the rectangular equation to a polar equation.
y^2x^2=7sqrt(x^2+y^2)
 one year ago
 one year ago
meww Group Title
Convert the rectangular equation to a polar equation. y^2x^2=7sqrt(x^2+y^2)
 one year ago
 one year ago

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tkhunny Group TitleBest ResponseYou've already chosen the best response.1
\(x = r\cos(\theta)\) \(y = r\sin(\theta)\) Substitute and Simplify.
 one year ago

meww Group TitleBest ResponseYou've already chosen the best response.0
i know that.. but what i got was rcos(2theta) = 7r and it says the answer is r=7/cos(2theta)
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Why didn't you say so? If you show your work, we can have a much better conversation much more quickly. \(x^{2} = r^{2}\cos^{2}(\theta)\) \(y^{2} = r^{2}\sin^{2}(\theta)\) \(\sqrt{x^{2} + y^{2}} = r\) And we're left with: \(r(\sin^{2}(x)  cos^{2}(x)) = 7\) Sure enough, exctly as you have it. So, what's the dilemma? Not the form allowed by the exam? Try cos(x) = 1/sec(x)
 one year ago
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