Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

meww Group Title

Convert the rectangular equation to a polar equation. y^2-x^2=7sqrt(x^2+y^2)

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. tkhunny Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \(x = r\cos(\theta)\) \(y = r\sin(\theta)\) Substitute and Simplify.

    • 2 years ago
  2. meww Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i know that.. but what i got was -rcos(2theta) = 7r and it says the answer is r=-7/cos(2theta)

    • 2 years ago
  3. tkhunny Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Why didn't you say so? If you show your work, we can have a much better conversation much more quickly. \(x^{2} = r^{2}\cos^{2}(\theta)\) \(y^{2} = r^{2}\sin^{2}(\theta)\) \(\sqrt{x^{2} + y^{2}} = r\) And we're left with: \(r(\sin^{2}(x) - cos^{2}(x)) = 7\) Sure enough, exctly as you have it. So, what's the dilemma? Not the form allowed by the exam? Try cos(x) = 1/sec(x)

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.