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math>philosophyBest ResponseYou've already chosen the best response.0
What is the range of each function?
 one year ago

math>philosophyBest ResponseYou've already chosen the best response.0
now satellite73 will help you
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
it might help to know that \(a\sin(x)+b\cos(x)=\sqrt{a^2+b^2}\sin(x+\theta)\) for suitable \(\theta\) that should help a great deal with the range
 one year ago

soty2013Best ResponseYou've already chosen the best response.0
asin(x)+bcos(x)=a2+b2−−−−−−√sin(x+θ) but how do you get this ?
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
square root is on the outside it is \(\sqrt{a^2+b^2}\sin(x+\theta)\) and it is a consequence of the "addition angle formula"
 one year ago

soty2013Best ResponseYou've already chosen the best response.0
@satellite73 i am having very problem in it... can you explain the function chapter from the starting, i will be very thankful to you..
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
i do not know exactly what you mean by "explain the function chapter" you could graph the function \[\sin(x)+\cos(x)\] using technology to see what you get or you could surmise that the largest the sum could be is if they were the same value, making \(\sin(x)=\frac{\sqrt{2}}{2}\) and also \(\cos(x)=\frac{\sqrt{2}}{2}\) and therefore the max would be \(\sqrt{2}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
or more simply you could use the formula i wrote above, telling you that \[\sin(x)+\cos(x)=\sqrt{2}\sin(x+\frac{\pi}{4})\] and now the range is more or less obvious
 one year ago
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