anonymous
  • anonymous
find the domain and range of (sin x + cos x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
how
anonymous
  • anonymous
What is the range of each function?
anonymous
  • anonymous
-1 to +1

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anonymous
  • anonymous
now ?
anonymous
  • anonymous
now satellite73 will help you
anonymous
  • anonymous
it might help to know that \(a\sin(x)+b\cos(x)=\sqrt{a^2+b^2}\sin(x+\theta)\) for suitable \(\theta\) that should help a great deal with the range
anonymous
  • anonymous
asin(x)+bcos(x)=a2+b2−−−−−−√sin(x+θ) but how do you get this ?
anonymous
  • anonymous
square root is on the outside it is \(\sqrt{a^2+b^2}\sin(x+\theta)\) and it is a consequence of the "addition angle formula"
anonymous
  • anonymous
@satellite73 i am having very problem in it... can you explain the function chapter from the starting, i will be very thankful to you..
anonymous
  • anonymous
i do not know exactly what you mean by "explain the function chapter" you could graph the function \[\sin(x)+\cos(x)\] using technology to see what you get or you could surmise that the largest the sum could be is if they were the same value, making \(\sin(x)=\frac{\sqrt{2}}{2}\) and also \(\cos(x)=\frac{\sqrt{2}}{2}\) and therefore the max would be \(\sqrt{2}\)
anonymous
  • anonymous
or more simply you could use the formula i wrote above, telling you that \[\sin(x)+\cos(x)=\sqrt{2}\sin(x+\frac{\pi}{4})\] and now the range is more or less obvious
anonymous
  • anonymous
Guru JEE thanks

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