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math>philosophy Group TitleBest ResponseYou've already chosen the best response.0
What is the range of each function?
 one year ago

math>philosophy Group TitleBest ResponseYou've already chosen the best response.0
now satellite73 will help you
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
it might help to know that \(a\sin(x)+b\cos(x)=\sqrt{a^2+b^2}\sin(x+\theta)\) for suitable \(\theta\) that should help a great deal with the range
 one year ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
asin(x)+bcos(x)=a2+b2−−−−−−√sin(x+θ) but how do you get this ?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
square root is on the outside it is \(\sqrt{a^2+b^2}\sin(x+\theta)\) and it is a consequence of the "addition angle formula"
 one year ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 i am having very problem in it... can you explain the function chapter from the starting, i will be very thankful to you..
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
i do not know exactly what you mean by "explain the function chapter" you could graph the function \[\sin(x)+\cos(x)\] using technology to see what you get or you could surmise that the largest the sum could be is if they were the same value, making \(\sin(x)=\frac{\sqrt{2}}{2}\) and also \(\cos(x)=\frac{\sqrt{2}}{2}\) and therefore the max would be \(\sqrt{2}\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
or more simply you could use the formula i wrote above, telling you that \[\sin(x)+\cos(x)=\sqrt{2}\sin(x+\frac{\pi}{4})\] and now the range is more or less obvious
 one year ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
Guru JEE thanks
 one year ago
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